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Andrews [41]
3 years ago
8

I've wasted 42 points already. Can someone PLZ just answer my Question and stop wasting my points. PLz, this is due. I need help

Mathematics
1 answer:
Misha Larkins [42]3 years ago
5 0

Step-by-step explanation:

You can put the value of x into the equation to solve for y. Hopes this works.

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What form is this equation in y= -3(x-5)^2+7 in?
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y= -3(x-5)^2+7

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2 years ago
Two buses leave towns 304 miles apart at the same time and travel toward each other. One bus travels 14 mih slower than the othe
8090 [49]

Answer:

The faster bus moves at 83mi/h and the slower one moves at 69mi/h.

Step-by-step explanation:

Let's define:

R₁ = rate of bus 1, this is the faster one.

R₂ = rate of bus 2, this is the slower one.

We know that one bus travels 14mi/h slower, then:

R₂ = R₁ - 14mi/h.

Now we know that:

Distance = Speed*Time.

If we add the distances that both busses travel in 2 hours, it should be equal to the initial distance between the buses, then:

R₁*2h + R₂*2h = 304 mi

Then we have the two equations:

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R₁*2h + (R₁ - 14mi/h)*2h = 304 mi

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The faster bus moves at 83mi/h

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