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Deffense [45]
2 years ago
13

Solve for x if sqrt (3x-8) + 1 = sqrt (x+5)

Mathematics
1 answer:
In-s [12.5K]2 years ago
5 0

The solution of x in the given expression \mathbf{\sqrt{(3x-8)}+1 = \sqrt{(x+5)}} is 4. However, if it is \mathbf{\sqrt{(3x-8)+1} = \sqrt{(x+5)}}, it is 6.

<h3>What is the solution to algebraic expression?</h3>

The solution to the given algebra expression involving surds can be seen in the steps below.

Given that:

\mathbf{\sqrt{(3x-8)}+1 = \sqrt{(x+5)}}

Remove the square roots, we have:

12x - 32 = 4x² - 48x + 144

Solving the quadratic equation at the RHS and equating it to LHS, we have:

x = 11, x = 4

Verifying the solutions by replacing the value of x with the given equation:

  • x = 11 False
  • x = 4 True

Therefore, we can conclude that the value of x = 4

NOTE:

Given that:

\mathbf{\sqrt{(3x-8+1)} = \sqrt{(x+5)}}

Square both sides

3x - 7 = x +5

Solve for x

3x - x = 5 + 7

2x = 12

x = 6

Learn more about solving to algebraic expressions here:

brainly.com/question/4344214

#SPJ1

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Step-by-step explanation:

Using log properties

log_{7}(rz {}^{12} )

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Then

log_{7}(r)  + 12 log_{7}(z)

Plug in the knowns

- 7.87 + 12( - 12.59)

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8 months ago
ill in the missing numbers along the sides of the triangle so that it contains each of the numbers from through exactly once. ​
mihalych1998 [28]

Each side of the triangle should contain four numbers whose sum is 28.

3+5+9+11=28

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11+6+9+7=28

The pain of numbers that can be used for A and B is [5,9] The pain of numbers that can be used for C and D is [10,8] and the pain of numbers that can be used for E and f is [6,4].

<h3>What are the 3 sides of a triangle?</h3>

The hypotenuse of a right triangle is its longest side; its "opposite" side is the one that faces the angle in question; and its "adjacent" side is the one that faces it. We use special terminology to define the sides of right triangles.

We use special terminology to define the sides of right triangles.

The side opposite the right angle is always the hypotenuse of a right triangle. It is the longest side in a right triangle.

The opposing and neighboring sides are the other two sides. The labels on these sides relate to an angle.

One side is across from another at a particular angle.

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1 year ago
Determine the most specific name for the figure in the diagram.
Makovka662 [10]
<span>ABCD is a parallelogram. Looking at the quadrilateral ABCD, the first thing to do is to determine if the opposite sides are parallel to each other. So let's check that by looking at the opposite sides. Line segment BA. When you go from point B to point A, you move to the right 1 space, and down 4 spaces. So the slope is -4. Looking at line segment CD, you also move to the right 1 space and down 4 spaces, which also means a slope of -4. So those two sides are parallel. When you compare line segments BC and AD, you'll notice that for both of them, you go to the right 5 spaces and up 2 spaces, so those too are parallel. So we can now saw that the quadrilateral ABCD is a parallelogram. Since ABCD is a parallelogram, we now need to check if it's a rectangle (we know it can't be a square since the sides aren't all the same length). An easy way to test if it's a rectangle is to check of one of the angles is 90 degrees. And if we draw a line from B to D, we can create a triangle ABD. And in a right triangle, due to Pythagora's theorem we know that A^2 + B^2 = C^2 where A is the line segment AB, B is the line segment AD and C is the line segment BD. So let's calculate A^2, B^2, and C^2. A^2: Line segment AB. We can construct a right triangle with A = 1 and B = 4. So C^2 = 1^2 + 4^2 = 1 + 16 = 17. So we have an A^2 value of 17 B^2: Line segment AD. We can construct a right triangle with A = 2 and B = 5. So C^2 = 2^2 + 5^2 = 4 + 25 = 29. So we have an B^2 value of 29 C^2: Line segment BD. We can construct a right triangle with A = 2 and B = 6. So C^2 = 2^2 + 6^2 = 4 + 36 = 40. So we have a C^2 value of 40. Now let's check if the equation A^2 + B^2 = C^2 is correct: 17 + 29 = 40 46 = 40 And since 46 isn't equal to 40, that means that ABCD can not be a rectangle. So it's just a parallelogram.</span>
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Dafna1 [17]
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Which of the sets of equations represent the two lines graphed?
Oksi-84 [34.3K]

Answer:

B) y = x + 2 and y = -x - 4

Step-by-step explanation:

Let the equation of a straight line with x-intercept 'a' and y-intercept 'b' be

\frac{x}{a}  +  \frac{y}{b}  = 1

The line with positive slope has x-intercept a=-2 and y-intercept b=2.

Its equation is:

\frac{x}{ - 2}  +  \frac{y}{2}  = 1

Multiply through by 2

- x + y = 2

Solve for y,

\boxed {y = x + 2}

For the line with a negative slope,

the x-intercept is a=-4 and the y-intercept is b=-4

Its equation is

\frac{x}{ - 4}  +  \frac{y}{ - 4}  = 1

Multiply through by -4

x + y =  - 4

Solve for y

\boxed {y =  - x - 4}

4 0
2 years ago
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