Question

You and your friend are selling raffle tickets for a new laptop. you sell 14 more then your friend sells. Together you and your friend sell 58 tickets. Write a system of linear equations that represent this situation. How many did each of you sell?

Answer 1

Answer:

$y=x+14$

$x+y=58$

You sold 22 tickets and your friend sold 36 tickets.

Step-by-step explanation:

1. Let´s name the variables as the following:

x = quantity of tickets sold by you

y = quantity of tiquets sold by your friend

2. As you sold 14 more than your friend, the first equation is:

$y=x+14$ (Eq.1)

3. As together sold 58 tickets, the second equation is:

$x+y=58$ (Eq.2)

4. Replacing the Eq. 1 in Eq. 2:

$x+x+14=58$

$2x+14=58$

$2x=58-14$

$2x=44$

$x=\frac{44}{2}$

$x=22$

Then you sold 22 tickets

5. Replacing the value of x result in Eq.1:

$y=x+14$

$y=22+14$

$y=36$

Therefore your friend sold 36 tickets.

Answer 2

X - 14 = y
x + y = 58

x is the amount you sold 
y is the amount your friend sold