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3 years ago

A rational number is

Mathematics

2 answers:

tatyana61 [14]3 years ago

7 0

Rational numbers can be written as fractions, can b whole numbers and is repeating decimals!

almond37 [142]3 years ago

5 0

Answer:

A rational number is a number that can be written as a fraction, is a whole number, is a decimal that stops like 3.35, or is a repeating decimal

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Charlie runs at a speed of 3 yd./s about how many miles per hour does Charlie run

vagabundo [1.1K]

1 hour = 3600 seconds

3 × 3600 = 10800

10800 yards per hour

1 mile = 1760 yards

10800 ÷ 1760 = 6.13

6.13 miles per hour

4 0

3 years ago

What is the best way to answer this mixed number 7 3/4 + 1 5/6

olga_2 [115]

9514 1404 393

Answer:

9 7/12

Step-by-step explanation:

12 is a suitable common denominator.

(7 3/4) + (1 5/6) = (7 9/12) + (1 10/12) = (7+1) +(9/12 +10/12)

= 8 + 19/12 = 9 + 7/12 . . . . . . change 19/12 to 1 7/12

= 9 7/12

_____

My calculator works with mixed numbers very nicely, as many graphing calculators do.

8 0

3 years ago

Read 2 more answers

The residents of a city voted on whether to raise property taxes. The ratio of yes votes to no votes was 7 to 5 . If there were

Nitella [24]

Answer: 6456

Step-by-step explanation:

Ratio of yes to no= 7:5

Number if yes= 3766

Since total number of yes is 3766. To find the total number of votes, 3766 / (7/7+5)

= 3766/ (7/12)

= 3766 × 12/7

= 45192/7

= 6456

There were 6456 total votes

5 0

3 years ago

Construct a 99% confidence interval for the population mean, mu. Assume the population has a normal distribution. A group of 1

Zarrin [17]

Answer:

99% confidence interval for the population mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean age of selected students = 22.4 years

s = sample standard deviation = 3.8 years

n = sample of students = 19

$\mu$ = population mean

Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.878 < $t_1_8$ < 2.878) = 0.99 {As the critical value of t at 18 degree of

freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.878) = 0.99

P( $-2.878 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.878 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

99% confidence interval for $\mu$ = [ $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ]

= [ $22.4 -2.878 \times {\frac{3.8}{\sqrt{19} }$ , $22.4 +2.878 \times {\frac{3.8}{\sqrt{19} }$ ]

= [19.891 , 24.909]

Therefore, 99% confidence interval for the population mean is [19.891 , 24.909].

6 0

3 years ago

WILL GIVE BRAINLIEST!

lesya [120]

Answer:

425

Step-by-step explanation:

225/24 then multiply the answer by 40

6 0

3 years ago