-.5 or negative 1/-2
same thing just in a dec and frac
The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
distance=(15 m/s)(3 s)=45 m
Distance traveled by car A =x, (when the car B is at the same distance from the start line)
time of car A=t
x=10 m/st ⇒ x=10t (1)
Distance traveled by car B=x
time of car B=t-3
x=15(t-3) (2)
With the equations (1) and (2) we make a system of equations:
x=10t
x=15(t-3)
We solve this system of equations:
10t=15(t-3)
10t=15t-45
-5t=-45
t=-45 / -5
t=9
t-3=9-3=6
x=10 t=10 (9)=90
Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
Answer:
The number is 12
Step-by-step explanation:
Let x be the number
160/100 = 1.6
1.6 x = 19.2
x = 19.2 / 1.6
x = 12
we are given
-3 x 2(4-18) + 8 =
Firstly , we will solve inside parenthesis
now, we can multiply
............Answer
Adding a positive to a negative, you would look at the number with the greater absolute value, and that number would determine the sign of the sum.
5 - 3 = 2
Since 5 is bigger, you use that sign
-5
-2
Answer: -2
