3 years ago

Assume the random variable X is normally distributed, with mean of 50 and a standard deviation of 9. Find the 9th percentile.

Mathematics

1 answer:

vovangra [49]3 years ago

7 0

Answer:

37.94

Step-by-step explanation:

the 9th percentile is equal to a zscore of -1.34

-1.34=(x-50)/9

x=37.94

You might be interested in

Any one that knows this please help thanks!

nignag [31]

You just need to plug the values: you have to multiply $x$ and $y^2$ , and then divide the result by -3.

So, if $y=2$ , we have $y^2=4$

Which means that $xy^2 = 5\cdot 4 = 20$

And the final answer is $\frac{20}{-3}$

3 0

2 years ago

What is the name of an account managed by a third party who makes

Andrej [43]

D the Escrow Account

6 0

3 years ago

Read 2 more answers

Pls hurry I’m being

kati45 [8]

D. Warm air rises and cool air sinks

7 0

2 years ago

Find the equation of a line given the point and slope below. Arrange your answer in the form y = mx + b, where b is the constant

Dvinal [7]

Answer:

y = 2x + 1

Step-by-step explanation:

Given a point and the slope, we can plug in these values into the equation to find the value of b:

y = mx + b

3 = 2(1) + b

3 = 2 + b

1 = b

Plug b into the equation:

y = 2x + 1

6 0

3 years ago

Read 2 more answers

Find the coordinates of the midpoint of the segment whose endpoints are h(6,4) and k(2,8)

ozzi

Answer:

$(4,6)$

Step-by-step explanation:

we know that

The formula to calculate the coordinates of the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

we have that

The coordinates of hk

$h(6,4), k(2,8)$

substitute in the formula to calculate the midpoint

$M(\frac{6+2}{2},\frac{4+8}{2})$

$M(\frac{8}{2},\frac{12}{2})$

$M(4,6)$

7 0

3 years ago

Read 2 more answers

Assume the random variable X is normally​ distributed, with mean of 50 and a standard deviation of 9. Find the 9th percentile.

Assume the random variable X is normally distributed, with mean of 50 and a standard deviation of 9. Find the 9th percentile.