Assume the random variable X is normally distributed, with mean of 50 and a standard deviation of 9. Find the 9th percentile.
1 answer:
Answer:
37.94
Step-by-step explanation:
the 9th percentile is equal to a zscore of -1.34
-1.34=(x-50)/9
x=37.94
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The value of a should be 2000. Hope this helps.
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did i ask shut man stop cheating
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