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3 years ago

If gross pay is $1500, what will the net pay be after 23% total deduction?

Mathematics

1 answer:

Ierofanga [76]3 years ago

6 0

Answer:2000

Step-by-step explanation:I think

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Which statement is true

satela [25.4K]

It would be the first one

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is the measure of the marked angle?

Alenkinab [10]

Answer: none of the above

Step-by-step explanation:

this is complementary angle meaning two angles have to add up to 90 degrees.

the only answer is 45 degrees which is not listed as an option so it is none of the above

4 0

2 years ago

Find the average value of f(x+y)=sin(x+y) over

Troyanec [42]

For each given region $D$ , the average value of $f$ over $D$ is the integral of $f$ over $D$ divided by the area of $D$ . In both cases, $D$ is a rectangle so the area is trivial.

a. The area of $D$ is $\dfrac\pi3\cdot\dfrac{5\pi}3=\dfrac{5\pi^2}9$ . The integral of $f$ over $D$ is

$\displaystyle\int_0^{5\pi/3}\int_0^{\pi/3}\sin(x+y)\,\mathrm dx\,\mathrm dy$

$\displaystyle=\int_0^{5\pi/3}\left(\cos y-\cos\left(y+\dfrac\pi3\right)\right)\,\mathrm dy$

$=\sin\dfrac{5\pi}3-\sin\left(\dfrac{5\pi}3+\dfrac\pi3\right) - \sin0+\sin\dfrac\pi3=0$

So the average value of $f$ over this region is 0.

b. The area of $D$ is $\dfrac{2\pi}3\cdot\dfrac{7\pi}6=\dfrac{7\pi^2}9$ . The integral of $f$ is

$\displaystyle\int_0^{7\pi/6}\int_0^{2\pi/3}\sin(x+y)\,\mathrm dx\,\mathrm dy$

$=\displaystyle\int_0^{7\pi/6}\left(\cos y-\cos\left(y+\frac{2\pi}3\right)\right)\,\mathrm dy$

$=\sin\dfrac{7\pi}6-\sin\left(\dfrac{7\pi}6+\dfrac{2\pi}3\right) - \sin0+\sin\dfrac{2\pi}3=\dfrac{\sqrt3}2$

The average vale of $f$ over this region is then $\dfrac{\frac{\sqrt3}2}{\frac{7\pi^2}9}=\dfrac{9\sqrt3}{14\pi^2}$ .

4 0

2 years ago

I need help with this problem

qaws [65]

Answer:

It's 6/7

Step-by-step explanation:

5 0

2 years ago

F(x) = 6x2 + 2x − 7 and g(x) = 4x − 3. <br> a. (f+g)(x)<br><br> b. (f-g)(x)

ELEN [110]

Answer:

a) (f+g)(x) = 6x^2 +6x -10

b) (f-g)(x) = 6x^2 -2x -4

Step-by-step explanation:

a. (f+g)(x) = f(x) +g(x) = (6x^2 +2x -7) +(4x -3)

(f+g)(x) = 6x^2 +6x -10

b. (f-g)(x) = f(x) -g(x) = (6x^2 +2x -7) -(4x -3)

(f-g)(x) = 6x^2 +2x -7 -4x +3

(f-g)(x) = 6x^2 -2x -4

8 0

3 years ago