Answer:
A
Step-by-step explanation:
We can find a common denominator for all of these fractions, compute, and then compare the values to find the right answer.
Just take both sides multiply by 2 then divide 3
Answer:
$18.36
Step-by-step explanation:
In this question, we have to find the cost of the cake for the customer who orders a month early.
We know that the original price of the cake is $30.
We also know that there was a 28% discount and a 15% discount added to the purchase.
Remember, You don't add discount percentages together, you discount the prices separately.
Solve:
First, apply the 28% discount.
30 · 0.28 = 8.40
30 - 8.40 = 21.60
Now apply the 15% discount to the new price.
21.60 · 0.15 = 3.24
21.60 - 3.24 = $18.36
They needed to pay $18.36 for the cake.
The solution to the given differential equation is yp=−14xcos(2x)
The characteristic equation for this differential equation is:
P(s)=s2+4
The roots of the characteristic equation are:
s=±2i
Therefore, the homogeneous solution is:
yh=c1sin(2x)+c2cos(2x)
Notice that the forcing function has the same angular frequency as the homogeneous solution. In this case, we have resonance. The particular solution will have the form:
yp=Axsin(2x)+Bxcos(2x)
If you take the second derivative of the equation above for yp , and then substitute that result, y′′p , along with equation for yp above, into the left-hand side of the original differential equation, and then simultaneously solve for the values of A and B that make the left-hand side of the differential equation equal to the forcing function on the right-hand side, sin(2x) , you will find:
A=0
B=−14
Therefore,
yp=−14xcos(2x)
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Answer:
Step-by-step explanation:
+6x-5=0
we divide the coefficient of the X by half :
in this case: 6/2 = 3 , then we do the following
The result obtained is raised to square power: 3^2=9
we sum and subtract by 9 to maintain the balance of the equation:
+6x+9-9-5=0
we have:
-9-5=0
= 14
lets apply square root on both sides of the equation:
we know:
so we have:
abs(x+3)=
from where two solutions are obtained
finally we have:
