Question

How to solve for X in the triangle

Answer 1

Answer:

$x = 16\sqrt{2}$

Step-by-step explanation:

we are given a right triangle.

then

In order to determine x we need to use

the Pythagorean theorem:

$x^{2}+8^{2}=24^{2}$

⇔ x² + 64 = 576

⇔ x² = 576 - 64

⇔ x² = 512

⇔ x² = 2⁹

⇔ x² = 2 × 2⁸

$\Longleftrightarrow x=\sqrt{2\times 2^{8}} =\sqrt{2\times \left( 2^{4}\right)^{2} }$

$\Longleftrightarrow x= \sqrt{\left( 16\right)^{2} } \times \sqrt{2$

$\Longleftrightarrow x = 16\sqrt{2}$

Answer 2

Answer:

22.6

Step-by-step explanation:

a^2+b^2=c^2

8^2+b^2=24^2

b^2=512

b=22.6