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Fantom [35]
2 years ago
6

If t is the midpoint of segment rs then, segment rt is congruent to segment ts.. help please!!!!

Mathematics
1 answer:
Zarrin [17]2 years ago
4 0

It is the definition of  Midpoint

Disclaimer!!!

The question is incomplete and the correct question is shown below

What definition would justify the following statement?

If T is the midpoint of segment RS then, Segment RT is congruent to segment TS..

  1. Definition of Angle Bisector
  2. Definition of Congruence
  3. Definition of Midpoint
  4. Definition of Segment Bisector

If t is the midpoint of segment rs then, segment rt is congruent to segment ts. is the definition of the midpoint

The line segment of a triangle connecting the midpoint of two sides of the triangle is said to be parallel to its third side and is also half the length of the third side, according to the midpoint theorem.

Hence It is the definition of the midpoint

Learn more about Midpoint here

brainly.com/question/5127660

#SPJ4

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What happens to the mean of the data set {2, 4, 7, 6, 3, 6, 7} if the number 25 is added?
Margaret [11]

Answer:

It goes up by 2.5

Step-by-step explanation:

Mean equation: (n₁ + n₂ + n₃ + ...)/n

Current mean: (2 + 4 + 7 + 6 + 3 + 6 + 7)/7 = 35/7 =<em> 5</em>

New mean: (2 + 4 + 7 + 6 + 3 + 6 + 7 + 25)/8 = 60/8 = <em>7.5</em>

Difference: 7.5 - 5 = 2.5

8 0
3 years ago
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Enter the equivalent distance in km in the box.
Delvig [45]
It is .6 of a kilometer 
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3 years ago
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Find the distance between points M (6,16) and Z (-1,14) to the nearest tenth, please help step by step
insens350 [35]
The distance between 2 points P(a, b) and Q(c,d) is given by the formula:

\displaystyle{d= \sqrt{(b-d)^2+(a-c)^2}, 


Apply the formula for the points M(6, 16) and Z(-1, 14):

\displaystyle{d= \sqrt{(16-14)^2+(6-(-1))^2}= \sqrt{2^2+7^2}= \sqrt{4+49}= \sqrt{53}\approx 7.28

which rounded to the nearest tenth is 7.3 (units)

Answer: 7.3 units
3 0
3 years ago
Help me with these 3 questions, please
Zina [86]

Answer:

1. x = -4y ---> y = (-1/4)x

slope = -1/4. y-intercept = (0,0)

2. y = -2x + 4

3. y = (1/3)x - 1

Step-by-step explanation:

1. Re-write your equation so that x is on the right and y is on the left:

x = -4y ---> y = (-1/4)x

slope = -1/4. y-intercept = (0,0)

2. y-intercept = (0,4) ----> P1

x-intercrpt = (2,0) ----> P2

slope m = (y2 - y1) / (x2 - x1)

= (0 - 4)/(2 - 0)

= -2

therefore, y - y1 = mx - x1 ---> y - 4 = -2x

or y = -2x + 4

3. y-intercept = (0,-1)

x-intercept = (3,0)

m = (0 - (-1)) / (3 -0) = 1/3

y - (-1) = (1/3)x - 0 ---> y = (1/3)x - 1

5 0
3 years ago
PLEASE HELP! FIND THE SURFACE AREA OF THIS SQUARE-BASED PYRAMID. I REALLY NEED HELP
jolli1 [7]

Answer:

105

For the 4 triangular faces, find the area with 1/2 × base × height = 1/2 × 5 × 8 = 20

4 triangles -> 20 × 4 = 80

The area of the square base is 25

80 + 25 - 105 cm^{2}

3 0
3 years ago
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