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Dmitry_Shevchenko [17]
2 years ago
7

Given that f(x) = x² +8x+3 and g(x) = -x-7, which of the following is true?

Mathematics
1 answer:
Valentin [98]2 years ago
4 0
B and C make sense to me.
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What is the slope of this table<br> х<br> у<br> 0<br> 1<br> 1<br> 4<br> 2<br> 4<br> 7<br> 13<br> 16
Jobisdone [24]

Answer:

THE ANSWER IS 222

Step-by-step explanation:

5 0
3 years ago
I didn’t study and it’s 2 am pls help
AlexFokin [52]

Answer: 7. g = -50, 8. f= 340/6 9. 3 10 .125

Step-by-step explanation:#7 g(3): 4(3)^2 +6 =12^2 +6 = 1444=6= 150. We divide 150 by 3 giving us -50.  #8We start by putting f(6): -3(6)^2 -4(6) +8. We use PEMDAS. -18^2 -24 +8 = _324-24+8 F= 340/6 #9 g(15) = Square root of 15-6=9 and the square root of 9 is 3, therefore, the answer is 3. #10 h (x) = 2^x we plug -3 to 2^-3. It is a negative number and it gives us .125 or 12.5

3 0
3 years ago
Read 2 more answers
Below is the step-by-step solution to the prob-
MakcuM [25]

Answer:

Step-by-step explanation:

-4 + 4x = -pq

Add 4 to both sides

4x = -pq + 4

Divide both sides by 4

x = \frac{-pq + 4}{4}

3 0
3 years ago
Hello? STOP RIGHT THERE.... Please help me with this.
matrenka [14]

Answer: THE ANSWER IS 2 :)

Step-by-step explanation:

3(q+2)  Do distributive property

3q=6 Divide 3q to both side

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6 0
3 years ago
For all values of x
Yuliya22 [10]

Answer:

A.) gf(x) = 3x^2 + 12x + 9

B.) g'(x) = 2

Step-by-step explanation:

A.) The two given functions are:

f(x) = (x + 2)^2 and g(x) = 3(x - 1)

Open the bracket of the two functions

f(x) = (x + 2)^2

f(x) = x^2 + 2x + 2x + 4

f(x) = x^2 + 4x + 4

and

g(x) = 3(x - 1)

g(x) = 3x - 3

To find gf(x), substitute f(x) for x in g(x)

gf(x) = 3( x^2 + 4x + 4 ) - 3

gf(x) = 3x^2 + 12x + 12 - 3

gf(x) = 3x^2 + 12x + 9

Where

a = 3, b = 12, c = 9

B.) To find g '(12), you must first find the inverse function of g(x) that is g'(x)

To find g'(x), let g(x) be equal to y. Then, interchange y and x for each other and make y the subject of formula

Y = 3x + 3

X = 3y + 3

Make y the subject of formula

3y = x - 3

Y = x/3 - 3/3

Y = x/3 - 1

Therefore, g'(x) = x/3 - 1

For g'(12), substitute 12 for x in g' (x)

g'(x) = 12/4 - 1

g'(x) = 3 - 1

g'(x) = 2.

5 0
3 years ago
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