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3 years ago

A polynomial has zeros of -1(mult. 2), 2 and 3

1 answer:

5 0

Answer= x^4 - 3x^3 - 3x^2 + 7x +6

1. Write out the 0s
(x + 1)(x + 1)(x - 2)(x - 3)
[[ remember the sign flips ]]

2. Foil the first two.
(x + 1)(x + 1)
x^2 + x + x + 1
x^2 + 2x + 1

3. Foil the second two.
(x - 2)(x - 3)
x^2 - 3x - 2x + 6
x^2 - 5x + 6

4. Foil both polynomials.
(x^2 + 2x + 1) (x^2 - 5x + 6)
..
It comes out as:
x^4 - 3x^3 - 3x^2 + 7x +6
You can check the pic for the work on that.

If you want, check your work by finding the 0s. They should be -1, 2, and 3. Also make sure the highest power is the number of 0s.
The highest power is ^4, and there are 4 zeros (since -1 is mult of 2)

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A pack of 24 cans costs £6. Work out the cost of 5 cans.

VARVARA [1.3K]

24 cans costs £6

6/24 = 0.25 each can

5 * 0.25 = £1.25

answer: £1.25 for 5 cans

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3 years ago

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Describe how to combine like terms in the expression 3n + 4n -2

storchak [24]

You can combine the same numbers with the same variables using the operation sign for each. For example, using your equation, you would combine the 3n and 4n which is 7n. So your equation would be
7n - 2

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3 years ago

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Here are the questions:

yaroslaw [1]

Answer:

Q1) 0.46 Q2)0.2333

Step-by-step explanation:

Q1) P=(4+12+7)/50 =0.46

Q2) P=7/(4+7+10+9)

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3 years ago

Allan and Dave bowl together and their combined total score for one game was 375 points. Allan’s score was 60 less than twice Da

Bess [88]

A system of equations is:
B )
x + y = 375
x = 2 y - 60
We will solve this system:
2 y - 60 + y = 375
3 y = 435
y = 435 : 3
y = 145
x = 375 - 145
x = 230
Allan`s score was 230 and Dave`s score was 145.

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3 years ago

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Give the equation of the line perpendicular to y +7= -2(x - 6) through the point (6,-3)

lilavasa [31]

Note: this answer assumes the equation of the line can be put in slope-intercept form.

Answer:

$y + 3 = \frac{1}{2}(x-6)$

Step-by-step explanation:

1) First, find the slope of y + 7 = -2 (x - 6). We can see that it's already in point-slope form, or $y-y_1 = m (x-x_1)$ format. Remember that the number in place of the $m$ is the slope. Therefore, -2 is the slope of that equation.

What we need is the slope that is perpendicular to that, though. So, find the opposite reciprocal of -2. To do this, change its sign, convert it into a fraction ( $-\frac{2}{1}$ ), and flip its numerators and denominators. Therefore, the perpendicular slope would be $\frac{1}{2}$ .

2) Now that we have a slope and a point the line passes through, we can write an equation using the point-slope formula, $y-y_1 = m (x-x_1)$ . In order to write an equation, the $x_1$ , $y_1$ , and $m$ have to be substitute for with real values.

The $m$ represents the slope. We already calculated that in the last step, so put $\frac{1}{2}$ in place of the $m$ . The $x_1$ and $y_1$ represent the x and y values of a point the line passes through. We know that the line has to pass through (6, -3), so substitute 6 for $x_1$ and -3 for $y_1$ :

$y - (-3) = \frac{1}{2}(x -(6))\\y + 3 = \frac{1}{2}(x - 6)$

Therefore, (again, assuming that the line can be put in point-slope form) the answer is $y + 3 = \frac{1}{2}(x-6)$ .

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3 years ago