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andrey2020 [161]
3 years ago
15

A polynomial has zeros of -1(mult. 2), 2 and 3

Mathematics
1 answer:
igomit [66]3 years ago
5 0
Answer= x^4 - 3x^3 - 3x^2 + 7x +6

1. Write out the 0s
(x + 1)(x + 1)(x - 2)(x - 3)
[[ remember the sign flips ]]

2. Foil the first two.
(x + 1)(x + 1)
x^2 + x + x + 1
x^2 + 2x + 1

3. Foil the second two.
(x - 2)(x - 3)
x^2 - 3x - 2x + 6
x^2 - 5x + 6

4. Foil both polynomials.
(x^2 + 2x + 1) (x^2 - 5x + 6)
..
It comes out as:
x^4 - 3x^3 - 3x^2 + 7x +6
You can check the pic for the work on that.

If you want, check your work by finding the 0s. They should be -1, 2, and 3. Also make sure the highest power is the number of 0s.
The highest power is ^4, and there are 4 zeros (since -1 is mult of 2)
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Allan and Dave bowl together and their combined total score for one game was 375 points. Allan’s score was 60 less than twice Da
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Give the equation of the line perpendicular to y +7= -2(x - 6) through the<br> point (6,-3)
lilavasa [31]

<u>Note: this answer assumes the equation of the line can be put in slope-intercept form. </u>

Answer:

y + 3 = \frac{1}{2}(x-6)

Step-by-step explanation:

1) First, find the slope of y + 7 = -2 (x - 6). We can see that it's already in point-slope form, or y-y_1 = m (x-x_1) format. Remember that the number in place of the m is the slope. Therefore, -2 is the slope of that equation.

What we need is the slope that is perpendicular to that, though. So, find the opposite reciprocal of -2. To do this, change its sign, convert it into a fraction (-\frac{2}{1}), and flip its numerators and denominators. Therefore, the perpendicular slope would be \frac{1}{2}.

2) Now that we have a slope and a point the line passes through, we can write an equation using the point-slope formula, y-y_1 = m (x-x_1). In order to write an equation, the x_1, y_1, and m have to be substitute for with real values.

The m represents the slope. We already calculated that in the last step, so put \frac{1}{2} in place of the m. The x_1 and y_1 represent the x and y values of a point the line passes through. We know that the line has to pass through (6, -3), so substitute 6 for x_1 and -3 for y_1:

y - (-3) = \frac{1}{2}(x -(6))\\y + 3 = \frac{1}{2}(x - 6)

Therefore, (again, assuming that the line can be put in point-slope form) the answer is y + 3 = \frac{1}{2}(x-6).

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3 years ago
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