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andrey2020 [161]
3 years ago
15

A polynomial has zeros of -1(mult. 2), 2 and 3

Mathematics
1 answer:
igomit [66]3 years ago
5 0
Answer= x^4 - 3x^3 - 3x^2 + 7x +6

1. Write out the 0s
(x + 1)(x + 1)(x - 2)(x - 3)
[[ remember the sign flips ]]

2. Foil the first two.
(x + 1)(x + 1)
x^2 + x + x + 1
x^2 + 2x + 1

3. Foil the second two.
(x - 2)(x - 3)
x^2 - 3x - 2x + 6
x^2 - 5x + 6

4. Foil both polynomials.
(x^2 + 2x + 1) (x^2 - 5x + 6)
..
It comes out as:
x^4 - 3x^3 - 3x^2 + 7x +6
You can check the pic for the work on that.

If you want, check your work by finding the 0s. They should be -1, 2, and 3. Also make sure the highest power is the number of 0s.
The highest power is ^4, and there are 4 zeros (since -1 is mult of 2)
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Second one:

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Step-by-step explanation:

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umka21 [38]

Answer:

Following are the solution to the given question.

Step-by-step explanation:

Please find the graph file and its solution in the attachment.  

4x-15=3x+28\\\\4x-3x=28+15\\\\x=43\\\\

Similarly:

3y+5=2y+50\\\\3y-2y=-5+50\\\\y=45\\\\

For point 1:\to KR=4x-15= 4\times 43-15=172-15=157

For point 2: \to BR=2y+50= 2\times 43+50=86+50=136

For point 3:\to BE=KR=157

For point 4:\to Kf=BR=130

For point 5:\to ERK=KFB=180^{\circ} -\angle B-\angle ERB = 180^{\circ}-92^{\circ}-18^{\circ}=70^{\circ}

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