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3 years ago

Help help help please

Mathematics

1 answer:

Debora [2.8K]3 years ago

6 0

Answer:

Step-by-step explanation:

the line is going from left to right ot has a negative gradient

as it goes through (0,0) euqally it is y = -x

You might be interested in

Write 321.35 in scientific form.

konstantin123 [22]

Answer:

3.2135 x 10^2 if you're looking for scientific notation

Step-by-step explanation:

8 0

3 years ago

Lenny rolls two number cubes. What is the probability that the sum of the numbers Lenny rolls is either 4 or 7?

Mashutka [201]

Probability of an event =

(number of ways the event can happen) / (total number of possible outcomes) .

Well, the total number of possible outcomes is easy. It's

(6 possibilities for the first cube) x (6 possibilities for the 2nd cube)

= 36 total possible ways for two cubes to roll.

Now, how many of those possibilities show either 4 or 7 ?

Well, here's how a 4 can come up:

1 . . . 3

2 . . . 2

3 . . . 1

and here's how a 7 can come up:

1 . . . 6

2 . . . 5

3 . . . 4

4 . . . 3

5 . . . 2

6 . . . 1 .

So there are 9 ways all together for Lenny to be successful.

The probability is (9/36) .

That's 1/4 , or 25% .

7 0

3 years ago

Read 2 more answers

If Benito is selecting samples of five values from the table, which row will result in the greatest mean? Population Data Row 1

Vilka [71]

Answer:

4th row will result in the greatest mean.

Step-by-step explanation:

We are asked to find the row with greatest mean from our given rows.

We will use formula $\bar{x}=\frac{\Sigma x}{n}$ , where,

$\bar{x}=\text{Mean}$ ,

$\Sigma x=\text{Sum of all data values}$ ,

$n=\text{Number of data points in sample}$

Let us find mean of each row using above formula.

$\text{Mean of row 1}=\frac{4+2+2+3+3}{5}$

$\text{Mean of row 1}=\frac{14}{5}$

$\text{Mean of row 1}=2.8$

Therefore, mean of 1st row is 2.8.

$\text{Mean of row 2}=\frac{3+3+4+3+2}{5}$

$\text{Mean of row 2}=\frac{15}{5}$

$\text{Mean of row 2}=3$

Therefore, mean of 2nd row is 3.

$\text{Mean of row 3}=\frac{2+4+3+4+3}{5}$

$\text{Mean of row 3}=\frac{16}{5}$

$\text{Mean of row 3}=3.2$

Therefore, mean of 3rd row is 3.2.

$\text{Mean of row 4}=\frac{3+4+4+7+3}{5}$

$\text{Mean of row 4}=\frac{21}{5}$

$\text{Mean of row 4}=4.2$

Therefore, mean of 4th row is 4.2.

Since 4th row has the highest mean, therefore, 4th row will result in the greatest mean.

6 0

3 years ago

Read 2 more answers

on a certain hot Summer's Day 613 people use the public swimming pool the daily prices are $1.75 for children $2.25 for adults t

Elodia [21]

389 children and 224 adults were at the pool that day.

Step-by-step explanation:

Cost of one child ticket = $1.75

Cost of one adult ticket = $2.25

Total people = 613

Total receipts worth = $1184.75

Let,

Number of children = x

Number of adults = y

According to given statement;

x+y=613 Eqn 1

1.75x+2.25y=1184.75 Eqn 2

Multiplying Eqn 1 by 1.75

$1.75(x+y=613)\\1.75x+1.75y=1072.75\ \ \ Eqn\ 3$

Subtracting Eqn 3 from Eqn 2

$(1.75x+2.25y)-(1.75x+1.75y)=1184.75-1072.75\\1.75x+2.25y-1.75x-1.75y=112.00\\0.50y=112.00$

Dividing both sides by 0.50

$\frac{0.50y}{0.50}=\frac{112.00}{0.50}\\y=224$

Putting y=224 in Eqn 1

$x+224=613\\x=613-224\\x=389\\$

389 children and 224 adults were at the pool that day.

Keywords: linear equation, subtraction

Learn more about linear equations at:

#LearnwithBrainly

6 0

3 years ago

4.20. According to a report released by the National Center for Health Statistics, 51% of U.S. households has only cell phones (

Sergeu [11.5K]

Answer:

The probability that the household has only cell phones and has high-speed Internet is 0.408

Step-by-step explanation:

Let A be the event that represents U.S. households has only cell phones

Let B be the event that represents U.S. households have high-speed Internet.

We are given that 51% of U.S. households has only cell phones

P(A)=0.51

We are given that 70% of the U.S. households have high-speed Internet.

P(B)=0.7

We are given that U.S. households having only cell phones, 80% have high-speed Internet. A U.S household is randomly selected.

P(B|A)=0.8

$\frac{P(A\capB)}{P(A)}=0.8\\P(A\capB)=0.8 \times P(A)\\P(A\capB)=0.8 \times 0.51\\P(A\capB)=0.408$

Hence the probability that the household has only cell phones and has high-speed Internet is 0.408

7 0

3 years ago

Help help help please​

Help help help please