Your answer will be 406 hope this helps
hello :<span>
<span>an equation of the circle Center at the
A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =0 and b = 0 (Center at the origin)
r = OP....p(-8,3)
r² = (OP)²
r² = (-8-0)² +(3-0)² = 64+9=73
an equation of the circle that satisfies the stated conditions.
Center at the origin, passing through P(-8, 3) is : x² +y² = 73</span></span>
Answer:
c/8
Step-by-step explanation:
Answer:
The mid-point between the endpoints (10,5) and (6,9) is:
Step-by-step explanation:
Let (x, y) be the mid-point
Given the points
Using the formula to find the mid-point between the endpoints (10,5) and (6,9)

Here:

Thus,



Therefore, the mid-point between the endpoints (10,5) and (6,9) is: