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inn [45]
2 years ago
11

C= 6x+100 and c=10x+80 what number does x have to be for c to be the same on each equation?

Mathematics
1 answer:
slega [8]2 years ago
7 0

Answer:

x= 5 , for c to be same on each eqn

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Evaluate |a| - |b|, given a = 5, b = -3, and c = -2. 2 3 7 8
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Step-by-step explanation:

|5| - |-3| is 2

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What is the fraction 2-5 2 on top and 5 on bottom ) equivalent to?
Andrei [34K]

To get to simplest form find the greatest common factor, or the gcf, of both numbers. To do that find all of the factors and find the one with the highest value both numbers share. So 30 would have factors of 1, 2, 3, 5, 6, 10, 15, and 30, and 42 would have the factors of 1, 2, 3, 6, 7, 14, 21, and 42. Both numbers share the factors of 1, 2, 3, and 6 so the gcf is 6. Now divide both numbers by six to get your answer.

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3 years ago
F as a function of x is equal to the square root of quantity 4 x plus 6, g as a function of x is equal to the square root of qua
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4 0
3 years ago
Find the value of x such that the area of a triangle whose vertices have coordinates (6, 5), (8, 2) and (x, 11) is 15 square uni
Serjik [45]

Answer:

x =12\ or\ -8

Step-by-step explanation:

Given

(x_1,y_1) = (6,5)

(x_2,y_2) = (8,2)

(x_3,y_3) = (x,11)

Area = 15

Required

Find x

The area is calculated as thus:

Area = \frac{1}{2}|x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|

Substitute values

15 = \frac{1}{2}|6*(2 - 11) + 8*(11 - 5) + x(5 - 2)|

15 = \frac{1}{2}|6*(-9) + 8*(6) + x(3)|

15 = \frac{1}{2}|-54 + 48 + 3x|

15 = \frac{1}{2}|-6 + 3x|

Multiply through by 2

2 * 15 = \frac{1}{2}|-6 + 3x| * 2

30 = |-6 + 3x|

Remove absolute sign

30 = -6 + 3x\ or\ -30 = -6 + 3x

Add 6 to both sides

36 = 3x\ or\ -24 =  3x

Divide by 3

12 = x\ or\ -8 = x

x =12\ or\ -8

<em>So, the coordinates are (-8, 11) or (12,11)</em>

3 0
3 years ago
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