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rewona [7]
2 years ago
14

Assuming a normal distribution, families spends an average of $500 on their monthly cell phone bills with a standard deviation o

f $75. What is the probability a random families' bill is between $350 and $400
Mathematics
1 answer:
alexira [117]2 years ago
5 0

There is a 0.02275 to 0.0968 chance that a random family's bill will be between $350 and $400.

<h3>Calculating the probability</h3>

Provided that,

Mean of the population = 500

The standard deviation(S.D) of the population = 75

Assume,the variable in normal distribution = X

Z= (x- mean)/ S.D

Provided , x = $350 - $400

Z= 350-500/75 = -2(when x=$350)

Z= 400-500/75 = -1.3 (taken x= $400)

The probability that a household will spend between $350 and $400 monthly

P(350>X<400) = P( -2>Z<-1.3)

                        = 0.02275 to 0.0968 (from probability table)

Therefore, the final answer is 0.02275 to 0.0968.

Learn more about the probability here:

brainly.com/question/11234923

#SPJ4

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4 years ago
Algebra applications: find the value of x and y​
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5x-y=180-150

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5x+y=180-130

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