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alekssr [168]
3 years ago
15

Find the value of the expression 12.325-(2.34*3.9)

Mathematics
1 answer:
VLD [36.1K]3 years ago
8 0
12.325-(2.34x3.9)
12.325-(9.126)
3.199 ~3.2
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Help! what is the surface area of the prism? 128in^2, 768in^2, 384in^2, or 480in^2
Nimfa-mama [501]

Option C: 384 \ in^2 is the surface area of the prism

Explanation:

Given figure is a triangular prism.

We need to determine the surface area of the triangular prism.

The formula to find the surface area of the triangular prism is given by

S A=b h+(s 1+s 2+s 3) H

where b is the base of the triangle,

h is the height of the triangle,

s1,s2,s3 are the three sides of the triangle and

H is the height of the prism.

Let us substitute the values b=16 , h=6 , s1=16 , s2=10 , s3=10 and H=8 in the formula, we get,

SA=16(6)+(16+10+10)(8)

Simplifying, we get,

SA=96+(36)(8)

Multiplying the term, we get,

SA=96+288

Adding the terms, we have,

SA=384 \ in^2

Thus, the surface area of the prism is 384 \ in^2

Hence, Option C is the correct answer.

6 0
3 years ago
Write an equation that has a graph with the shape of y = x^2, but shifted left 3 units.
svetoff [14.1K]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}\\\\
--------------------\\\\

\bf % template detailing
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\

\bf \bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

now, with that template in mind, let's see

\bf y=x^2\implies 
\begin{array}{llll}
y=(&1x&-0)^2\\
&B&C
\end{array}

so, just change C to +3, thus C/B is 3/1
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The answer is A and E
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Answer:

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