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wlad13 [49]
3 years ago
6

The graph shows a proportional relationship.What is the unit rate? Enter your answer as an improper fraction in simplest form in

the box.

Mathematics
1 answer:
ruslelena [56]3 years ago
6 0
That is the slope
rise/run
we see we have (2/5,1/2)
rise is y, run is x
(x,y)
((1/2)/(2/5)=(1/2)(2/5)=2/10=1/5

unit rate is y=(1/5)x
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What are the coordinates of the pre-image of B'?
dimulka [17.4K]

Answer:

b. (-8, -2)

Step-by-step explanation:

Reflection across the x-axis

(x, y) ---> (x, -y)

B'(- 8, 2) ---> B( - 8, -2)

5 0
2 years ago
Read 2 more answers
O is the centre of the circle, EF is a tangent, angle BCE = 28°, angle ACD = 31°
andriy [413]

Answer

a. 28˚

b. 76˚

c. 104˚

d. 56˚

Step-by-step explanation

Given,

∠BCE=28°  ∠ACD=31°  &  line AB=AC .

According To the Question,

  • a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°

  • b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚

        thus , ∠ABC=76° .

  • c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,

Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°

Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)

∠DAB = 180° - 107° ⇔ 73°

& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°

Now, In Triangle ADC Sum of angles in a triangle is 180°

∠ADC = 180° - (31° + 45°)  ⇔  104˚

   

  • d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre  

For Diagram, Please Find in Attachment  

4 0
3 years ago
Pls solve this sum asap
GalinKa [24]
This is a square root meaning whatever number multiplied by itself equals it’s square root. The answer would be 4 on the outside and 3 on the inside

6 0
3 years ago
Read 2 more answers
What is the answer to this​
Alborosie
The answer to the question is b

$9 each hour she works + 7.50 fee
$7.50+$9h= $34.50
7 0
3 years ago
Write an equation of the line that passes through (1,2) and is parallel to the line y=-5x+4
valentinak56 [21]

Answer:

The equation of the Parallel line to the given line is  5x+y-7=0

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that the line y = - 5x+4 and point (1,2)

The equation of the Parallel line to the given line is  ax+by+k=0

Given straight line  5x + y -4 =0

The equation of the Parallel line to the given line is  5x+y+k=0

This line passes through the point (1,2)

             5x+y+k=0

            5(1)+2+k=0

⇒              7+k=0

                   k =-7

<u>Final answer:-</u>

The equation of the Parallel line to the given line is  5x+y-7=0

7 0
2 years ago
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