Answer:
The exact answer in terms of radicals is ![x = 5*\sqrt[3]{25}](https://tex.z-dn.net/?f=x%20%3D%205%2A%5Csqrt%5B3%5D%7B25%7D)
The approximate answer is 
(accurate to 5 decimal places)
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Work Shown:
Let ![y = \sqrt[5]{x^3}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%5B5%5D%7Bx%5E3%7D)
So the equation reduces to -7 = 8-3y
Let's solve for y
-7 = 8-3y
8-3y = -7
-3y = -7-8 ... subtract 8 from both sides
-3y = -15
y = -15/(-3) ... divide both sides by -3
y = 5
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Since and y = 5, this means we can equate the two expressions and solve for x
![\sqrt[5]{x^3} = 5](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E3%7D%20%3D%205)
Raise both sides to the 5th power
![x = \sqrt[3]{3125}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B3125%7D)
Apply cube root to both sides
![x = \sqrt[3]{125*25}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B125%2A25%7D)
![x = \sqrt[3]{125}*\sqrt[3]{25}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B125%7D%2A%5Csqrt%5B3%5D%7B25%7D)
![x = \sqrt[3]{5^3}*\sqrt[3]{25}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B5%5E3%7D%2A%5Csqrt%5B3%5D%7B25%7D)
Answer:
Option C. 3√3
Step-by-step explanation:
Please see attached photo for brief explanation.
In the attached photo, we obtained the following:
Opposite = a
Adjacent = 3
Hypothenus = 6
Angle θ = 60°
We can obtain the value of 'a' as follow:
Tan θ = Opposite /Adjacent
Tan 60° = a/3
Cross multiply
a = 3 x Tan 60°
But: Tan 60° = √3
a = 3 x Tan 60°
a = 3 x √3
a = 3√3
Therefore, the length of the altitude of the equilateral triangle is 3√3.
Answer:yes 2.324324 is a rational number
Step-by-step explanation:
2.3 and 2.30 both are the same but it’s in money so IDK
