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Pani-rosa [81]
3 years ago
6

A solution to the compound inequality 17 less than or equal to 3 - 2x less than or equal to 21 is given below. Choose the statem

ent that is true about the given solution.. . A] 17 less than or equal to 3 - 2x and 3 - 2x less than or equal to 21 B] 20 less than or equal to -2x and -2x less than or equal to 24 C] -10 greater than or equal to x and x greater than or equal to -12
Mathematics
1 answer:
aliina [53]3 years ago
6 0
<span>17<=3-2x<=21 subtract 3 14<=-2x<=18 divide by 2 7<=-x<=9 now mutiply whole inequality by -1, this will reveres the inequality -7>=x>=-9 or -9<=x<=-7 so there are mistakes in the line the corrected lines are 17 less than or equal to 3 - 2x and 3 - 2x less than or equal to 21 (line one) 14 less than or equal to -2x and -2x less than or equal to 18 (line two) -7 greater than or equal to x and x greater than or equal to -9 (line three)</span>
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Answer:

The spaceship will get to Alpha Centaur in time

Step-by-step explanation:

<u><em>The complete question in English is</em></u>

You're the commander of a spaceship. Your mission is to reach Alpha Centaur  in five years. The distance from the sun to Alpha Centaur is 2.5 x 10^13 miles. The distance  from Earth to Sun is approximately 9.3 x 10^7

miles. Your spaceship can travel  at the speed of light. You know that light can travel a distance of 5.88 x 10^12  miles in a year. Can you get to Alpha Centaur in time?

step 1

Find the time it takes for the spaceship to travel from Earth to the Sun

The distance from the Earth to Sun is equal to

9.3*10^7\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

using a proportion

\frac{5.88*10^{12}\ miles}{1\ year}=\frac{9.3*10^7\ miles}{x}\\\\x=(9.3*10^7)/5.88*10^{12}\\\\x=1.58*10^{-5} \ years

This time is very small in years

Convert to minutes

1.58*10^{-5} \ years=1.58*10^{-5} (365)(24)(60)=8.3\ min

step 2

Find the time it takes for the spaceship to travel from the Sun to Alpha Centaur

The distance from the the Sun to Alpha Centaur is equal to

2.5*10^{13}\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

using a proportion

\frac{5.88*10^{12}\ miles}{1\ year}=\frac{2.5*10^{13}\ miles}{x}\\\\x=(2.5*10^{13})/5.88*10^{12}\\\\x=4.25\ years

4.25\ years< 5\ years

therefore

The spaceship will get to Alpha Centaur in time

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