Answer:
- <u><em>P(M) = 0.4</em></u>
Explanation:
<u>1. Build a two-way frequency table:</u>
To have a complete understanding of the scenary build a two-way frequency table.
Major in math No major in math Total
Major in CS
No major in CS
Total
Major in math No major in math Total
Major in CS
No major in CS
Total 200
- <u>80 plan to major in mathematics:</u>
Major in math No major in math Total
Major in CS
No major in CS
Total 80 200
- <u>100 plan to major in computer science</u>:
Major in math No major in math Total
Major in CS 100
No major in CS
Total 80 200
- <u>30 plan to pursue a double major in mathematics and computer science</u>:
Major in math No major in math Total
Major in CS 30 100
No major in CS
Total 80 200
- <u>Complete the missing numbers by subtraction</u>:
Major in math No major in math Total
Major in CS 30 70 100
No major in CS 100
Total 80 120 200
Major in math No major in math Total
Major in CS 30 70 100
No major in CS 50 50 100
Total 80 120 200
<u>2. What is P(M), the probability that a student plans to major in mathematics?</u>
- P(M) = number of students who plan to major in mathematics / number of students
Answer: 250%
since, 100% = 100/100
250% = 250/100
Step-by-step explanation:
Answer:
See explanation
Step-by-step explanation:
If point R lies
of the way along line LM, closer to L than M, then

Find all needed ratios:
1. 
2. By segment addition postulate,

so

3. 
then

No there could be a repeating bar over two meaning that it will keep the same number
Lets say billiard balls are arranged in rows to form an equilateral triangle, then the first row consists of 1 ball, second row consists of 2 balls, and third row consists of 3 balls, and so on. So there must be
balls in the
row.
So, the total number of balls that forms the equilateral triangle with
rows is:
Let
and
be the total number of balls in the first and second arrangements respectively.
Then,
It has been said that there were 11 lesser balls in the second arrangement:
Since, 

multiplying both the sides by 2





Therefore,

So, there were 125 balls at the set.