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jek_recluse [69]

2 years ago

6

Identify an equation in point-alope form for the line perpendicular to y-x-7 that passes through (-2,-6).

1 answer:

Mazyrski [523]2 years ago

8 0

Answer:

$y + 6 = -1(x + 2).$

Step-by-step explanation:

Let's find the general equation of the given line:

$y - x - 7 = 0\\\\y = x + 7.$

We can see that $m = 1.$

Thus, the slope of any perpendicular line to the line $y = x + 7$ is $-1.$

Given that the perpendicular line passes through (-2, -6), its point-slope form equation is as given:

$y - y_1 = m(x - x_1)\\\\y - (-6) = -1(x - (-2))\\\\y + 6 = -1(x + 2).$

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200 students in a high school senior class are surveyed about what majors they intend to declare in college. Of the 200 students

dedylja [7]

Answer:

<u><em>P(M) = 0.4</em></u>

Explanation:

<u>1. Build a two-way frequency table:</u>

To have a complete understanding of the scenary build a two-way frequency table.

<u>Column and rows:</u>

Major in math No major in math Total

Major in CS

No major in CS

Total

<u>200 students:</u>

Major in math No major in math Total

Major in CS

No major in CS

Total 200

<u>80 plan to major in mathematics:</u>

Major in math No major in math Total

Major in CS

No major in CS

Total 80 200

<u>100 plan to major in computer science</u>:

Major in math No major in math Total

Major in CS 100

No major in CS

Total 80 200

<u>30 plan to pursue a double major in mathematics and computer science</u>:

Major in math No major in math Total

Major in CS 30 100

No major in CS

Total 80 200

<u>Complete the missing numbers by subtraction</u>:

Major in math No major in math Total

Major in CS 30 70 100

No major in CS 100

Total 80 120 200

Major in math No major in math Total

Major in CS 30 70 100

No major in CS 50 50 100

Total 80 120 200

<u>2. What is P(M), the probability that a student plans to major in mathematics?</u>

P(M) = number of students who plan to major in mathematics / number of students

P(M) = 80 / 200 = 0.4

5 0

4 years ago

Which percent is eguivalent to 2.5?<br><br> 1)2.5%<br> 2)25%<br> 3)250%<br> 4)2,500%

sertanlavr [38]

Answer: 250%

since, 100% = 100/100

250% = 250/100

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Given line LM and point R that lies on line LM, identify the following ratios given that point R lies a/b of the way along line

gavmur [86]

Answer:

See explanation

Step-by-step explanation:

If point R lies $\frac{a}{b}$ of the way along line LM, closer to L than M, then

$LR=ax\\ \\LM=bx$

Find all needed ratios:

1. $\dfrac{LR}{LM}=\dfrac{ax}{bx}=\dfrac{a}{b}$

2. By segment addition postulate,

$LR+RM=LM\\ \\RM=bx-ax=(b-a)x,$

so

$\dfrac{RM}{LM}=\dfrac{(b-a)x}{ax}=\dfrac{b-a}{a}$

3. $RL=LR=ax\\ \\RM=(b-a)x,$

then

$\dfrac{RL}{RM}=\dfrac{ax}{(b-a)x}=\dfrac{a}{b-a}$

5 0

4 years ago

If a fraction can be written as a repeating decimal, only

mars1129 [50]

No there could be a repeating bar over two meaning that it will keep the same number

5 0

3 years ago

* Some amount of billiard balls were arranged in an equilateral triangle. And 5 balls were extra. When the same set of billiard

Agata [3.3K]

Lets say billiard balls are arranged in rows to form an equilateral triangle, then the first row consists of 1 ball, second row consists of 2 balls, and third row consists of 3 balls, and so on. So there must be $n$ balls in the $n^{th}$ row.

So, the total number of balls that forms the equilateral triangle with $n$ rows is:

$1+2+3+4+5+....+n=\frac{n(n+1)}{2}$

Let $x_1$ and $x_2$ be the total number of balls in the first and second arrangements respectively.

Then,

$x_1=\frac{n(n+1)}{2} +5$

It has been said that there were 11 lesser balls in the second arrangement:

$x_2=\frac{1+(n+1)}{2} \times (n+1)-11=(n+1) \times \frac{(n+2)}{2} -11$

Since, $x_1=x_2$

$\frac{(n+1)}{2} \times n+5=\frac{(n+2)}{2} \times(n+1)-11$

multiplying both the sides by 2

$(n+1)\times n+10=(n+2)(n+1)-22$

$n+n^2=n^2+n+2n+2-22-10$

$2n=22+10-2$

$2n=30$

$n=15$

Therefore,

$x_1=\frac{(n+1)}{2}\times n+5=\frac{15+1}{2} \times 15+5=125$

So, there were 125 balls at the set.

4 0

3 years ago

Read 2 more answers