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3 years ago

Which value is equivalent to 48 ÷ ((2 + 6) × 2) − 1?

Mathematics

2 answers:

lozanna [386]3 years ago

8 0

Answer:

B) 2

Step-by-step explanation:

add the 2 and 6

them multiply 8 and 2

so then you would have, 48 divided by 16-1

then divide the 48 and 16

then subtract 3-1

Ivan3 years ago

5 0

Answer:

I have is -3

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Polygon ABCD is reflected and dilated to give polygon PQRS. The coordinates of the preimage are (2, 2), (6, 8), (12, 8), and (16

HACTEHA [7]

Answer: The scale factor of the dilation is 0.5.

Explanation:

It is given that ABCD is polygon which is reflected and dilated , then we get PQRS.

The vertices of ABCD are (2, 2), (6, 8), (12, 8), and (16, 2) respectively. The vertices of image PQRS are (11, 15),(9, 12), (6, 12), and (4, 15) respectively.

The reflection affects the coordinates but does not affect the length of the sides.

But when we talk about dilation it affects the length of sides according to the scale factor or a constant factor.

If a line segment AB is dilated by scale factor k then length of A'B' is k times length of AB.

$|A'B'|=k\times |AB|$ .... (1)

So we have to find any side length of preimage and the side length of that side in image. it means we have to find AB and PQ.

Use distance formula to find the side length.

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$AB=\sqrt{(8-2)^2+(6-2)^2}=\sqrt{36+16}=2\sqrt{13}$

$PQ=\sqrt{(9-11)^2+(12-15)^2}=\sqrt{4+9}=\sqrt{13}$

It is noticed that the size of side in preimage is $2\sqrt{13}$ and the size of same side in image is $\sqrt{13}$ .

Using equation (1), we get

$\sqrt{13}=k \times 2\sqrt{13}$

$k=\frac{1}{2}$

$k=0.5$

Hence, the value of scale factor is 0.5.

7 0

3 years ago

Read 2 more answers

What is the trigonometric ratio for cosn? enter your answer, as a simplified fraction, in the boxes. $$ triangle l m n with righ

hjlf

The trigonometric ratio will be Cos(n)=12/13

<h3>What will be the trigonometry ratio?</h3>

Given is a Right triangle LMN with right angle at M i.e. angle M = 90 degrees.

Given are the sides LM = 15, MN = 36, and LN = 39.

It says to find cos(n) = ?

So opposite side would be LM, adjacent side would be MN, and LN is the hypotenuse.

We know that the cosine ratio is given by :-

$Cos(n)=\dfrac{adjacent}{Hypotenuse}$

$Cos(n)=\dfrac{MN}{LN}$

$Cos(n)=\dfrac{36}{39}$

$Cos(n)=\dfrac{12}{13}$

Hence the required ratio will be $Cos(n)=\dfrac{12}{13}$

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2 years ago

Question: Antonio is working with a new geometric series generated by the equation A(n)=20(1.1)^n-1.His sister challenged him to

Mekhanik [1.2K]

Answer:

sum of 22nd = 1,428.05

sum of 23 to 40 is 932.53

Step-by-step explanation:

A(n)=20(1.1)^n-1

20 is the first term or a1

1.1 is the common ratio or r

A(22) = 20(1.1)^22-1

22nd term = 20(1.1)^21

22nd term = 148.00

sum of geometric sequence

formula

Sn = a1(1-r^n)/1-r

Sn = sum

a1 = first term

n = number of term

r = constant ratio

sum of 22nd = 1,428.05.

23 to 40 is 17 terms

Sequence: 23, 25.3, 27.83, 30.613, 33.6743, 37.04173, 40.745903 ...

The 17th term: 105.684378686

Sum of the first 17 terms: 932.528165548

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3 years ago

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MakcuM [25]

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1 year ago

NO LINKS!! PART 2: Find the EXACT area and Circumference of each circle

Tema [17]

Answer:

2. center: (2, 5); radius: 3; Area: 9π; Circumference: 6π

4. center: (0, 0); radius: 8; Area: 64π; Circumference: 16π

Step-by-step explanation:

The standard form equation for a circle is ...

(x -h)² +(y -k)² = r² . . . . . . center (h, k), radius r

The value of r is used in the formulas for area (A) and circumference (C):

A = πr²

C = 2πr

Comparing the given equation to the standard form, we see ...

(x -h)² +(y -k)² = r²

(x -2)² +(y -5)² = 9

(h, k) = (2, 5) . . . . center

r² = 9

This tells us ...

r = √9 = 3 . . . . radius

The Area formula uses r² directly:

Area = πr² = π(9)

Area = 9π

The Circumference formula uses r:

Circumference = 2π(3)

Circumference = 6π

Comparing the given equation to the standard form, we find ...

(h, k) = (0, 0) . . . . center

r² = 64 ⇒ r = √64 = 8 . . . . radius

Area = 64π

Circumference = 2π(8) = 16π

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2 years ago

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