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Bad White [126]
2 years ago
6

Solve for x: 5^x/5^14=1/5^5

Mathematics
2 answers:
pav-90 [236]2 years ago
6 0

Answer:

x = 9

Step-by-step explanation:

<h2>Law of exponents:</h2>

        \sf \dfrac{a^m}{a^n}=a^{m-n}\\\\\\ \dfrac{1}{a^m}=a^{-m}

\sf \dfrac{5^x}{5^{14}}=\dfrac{1}{5^5}\\\\5^{x -14} = 5^{-5}

Base are same. Compare the exponents.

 x - 14 = -5

        x = -5 + 14    {Addition property of equality}

        x = 9

mariarad [96]2 years ago
4 0

Answer:

\frac{1 \\ }{3125}

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Margaret has 16 yards of fabric and she is making dresses for z doll write the expression for the length of fabric used for each
emmasim [6.3K]
<h3>The expression for the length of fabric used for each doll is \frac{16}{z}\ yards</h3>

<em><u>Solution:</u></em>

Given that,

Margaret has 16 yards of fabric

she is making dresses for z doll

Therefore,

Total length of fabric = 16 yards

Number of dresses = z dolls

Therefore,

\text{ length of fabric used for each doll } = \frac{ \text{ Total length of fabric }} {\text{ z dolls }}\\\\\text{ length of fabric used for each doll } = \frac{16}{z}\ yards

Thus, the expression for the length of fabric used for each doll is \frac{16}{z}\ yards

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4 years ago
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Step-by-step explanation:

3 0
3 years ago
A 40-m-long chain hangs vertically from a cylinder attached to a winch. Assume there is no friction in the system and the chain
daser333 [38]

Answer:

a) W₁ = 78400 [J]

b)Wt = 82320 [J]  

Step-by-step explanation:

a) W = ∫ f*dl      general expression for work

If we have a chain with density of 10 Kg/m, distributed weight would be

9.8 m/s² * 10 kg   = mg

Total length of th chain is 40 m, and the function of y at any time is

f(y) = (40 - y ) mg   where ( 40 - y ) is te length of chain to be winded

At the beggining we have to wind 40 meters   y = 0 at the end of the proccess  y = 40 and there is nothing to wind then:

f(y) = mg* (40 - y )

W₁ =  ∫f(y) * dy    ⇒ W₁ = ∫₀⁴⁰ mg* (40 - y ) dy  ⇒ W₁ = mg [ ∫₀⁴⁰ 40dy - ∫₀⁴⁰ ydy

W₁ = mg [ 40*y |₀⁴⁰   -  1/2 * y²  |₀⁴⁰    ⇒  W₁ = mg* [ 40*40 - 1/2 (40)² ]

W₁ = mg * [1/2]     W₁ = 10*9,8* ( 800 )

W₁ = 78400 [J]

b) Now we can calculate work to do if we have a 25 block and the chain is weightless

W₂ = ∫ mg* dy     ⇒    W₂  = ∫₀⁴⁰ mg*dy   ⇒    W₂  = mg y |₀⁴⁰

W₂ = mg* 40   = 10*9.8* 40  

W₂ = 3920 [J]

Total work

Wt = W₁  +  W₂        ⇒    Wt = 78400 + 3920

Wt = 82320 [J]

6 0
3 years ago
X-14
DENIUS [597]

Step-by-step explanation:

it will be 14 times 2 which will be 28 length and 74 plus 74 which will be 148 for the both side wide.

7 0
4 years ago
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