Question

Last year, during an investigation of the time spent reading e-mails on a daily basis, researchers found that on Monday the average time was 50 minutes. Office workers claim that with the increased spam and junk mail, this time has now increased. To conduct a test, a sample of 25 employees is selected with the following results: sample mean

Answer 1

The sample mean value is 0.26.

According to the statement we have given that the

Monday the average time was 50 minutes and we have to find the sample mean.

So, the values become

H(not):μ≤50

H(a):μ>50

Right Tail

The significance level, of the given number of employees then

α=0.05

And The value of sample mean, is

Z=x - u/i*(n)^1/2

then the value becomes

Z = 5.6 - 5/1.2*(25)^1/2.

then after calculating

Z= 1.6/1.2*5

Z= 0.26 And

Here The value of sample mean is 0.26.

So, The sample mean value is 0.26.

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