Answer:
12 units
Step-by-step explanation:
Given that :
R(-3,2)
S(2,2)
T(2,-5).
The total length ;
Distance between two points : √[(x2 - x1)² + (y2 - y1)²]
Distance between R and S :
R = (-3,2)
S(2,2)
√[((2 - (-3))^2 + (2 - 2)^2]
Sqrt(5^2 + 0^2)
D1 = 5 units
Distance between S and T:
S(2,2)
T(2,-5).
D2 = √[(2 - 2)^2 + (-5 - 2)^2]
D2 = sqrt(0^2 + (-7)^2)
D2 = 7 units
Hence, total length = D1 + D2 = (5 + 7) = 12 units
Answer:
P(A) = 0.95
P(B) = 0.05
P(C) = 0.85
P(D) = 0.15
P(E) = 0.15
P(F) = 0.85
Step-by-step explanation:
Walk = x + 6
Bike = x
Driven = x
x + x + x + 6 = 24
combine like terms
3x + 6 = 24
subtract 6 from both sides
3x = 18
divide both sides by 3 to isolate x
x = 6
Walk = x + 6 = 6 + 6 = 12
12 students walk to school.
Answer:
103°
Step-by-step explanation:
The marked angles have the same measure, so ...
14x+7 = 12x +17
2x = 10 . . . . . subtract 12x+7
x = 5 . . . . . . . divide by 2
(14x +7)° = 77°
∠CEA is supplementary to the marked angles:
∠CEA = 180° -77°
∠CEA = 103°
