Answer:
I have no clue
Step-by-step explanation:
the question is only 2 points so it wont be bad if you get it wrong
sorry i cant help
Answer:
Step-by-step explanation:
a. 5^(6/8)
b. x^1/3
c. 7^(5/2)
Answer:
The expected number of floors the elevator stops at, not counting the ground floor is =
n*(1-(1-1/n)^m)
Step-by-step explanation:
Here, we want to know the expected number of floors the elevator stops at.
let X1,X2,X3,..Xn are indicator variable for which value =1 if at least one person stops on that floor otherwise value is 0
P(at least one person stops at floor Xj)=1-P(none of m people stops at floor j)
=1-(1-1/n)^m
here total number of floors on elevetor Stops X=X1+X2+X3+...+Xn
hence expected number of floors on elevetor Stops
E(X)=E(X1)+E(X2)+E(X3)...+E(Xn)
=(1-(1-1/n)^m )+(1-(1-1/n)^m )+(1-(1-1/n)^m )+(1-(1-1/n)^m )+..... n times
=n*(1-(1-1/n)^m)
415 in
take 8 times 6 four times and add them together
Answer:
4 2/5 x 5 1/2 = 24.2
Step-by-step explanation:
PLZZ MARK BRAINLIEST!!!
