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Dmitry_Shevchenko [17]
2 years ago
15

A machine fills bags with sweets there are 4275 sweets there are 28 sweets in each full bag the machine fills as many bags as po

ssible how many sweets are left must show your working
Mathematics
1 answer:
Katena32 [7]2 years ago
4 0

19 sweets are lefted.

Lets simplify the problem,

Maximum no. of bag filled by 4275 sweets

Through Simple Division we get,

4275/28 ~=152

Therefore , there is 4256 sweets in 152 bags

Therefore, 4275-4256=19 sweets are left

Learn more about Simple Subtraction on:

brainly.com/question/28014619

#SPJ4

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3 years ago
For the equations given below, which statement is true?
allochka39001 [22]

Answer: C. The equations have the same solution because the second equation can be obtained by adding 6 to both sides of the first equation.

Step-by-step explanation:

You know that the first equation is:

-3x-8=19

And the second equation is:

-3x-2=25

According to the Addition property of equality:

If a=b; then a+c=b+c

Then, you can add 6 to both sides of the first equation to keep it balanced. Then, you get:

-3x-8=19\\\\-3x-8+(6)=19+(6)

-3x-2=25

Therefore, you can observe that the second equation can be obtained by adding 6 to both sides of the first equation, therefore, the equations have the same solution.

If you want to verify this, you can solve for "x" from both equations:

- First equation:

-3x-8=19\\\\-3x=19+8\\\\x=\frac{27}{-3}\\\\x=-9

- Second equation:

-3x-2=25\\\\-3x=25+2\\\\x=\frac{27}{-3}\\\\x=-9

5 0
3 years ago
3.) 2x + 4 = -3x - 2; x = 1<br><br>Determine if the value of x is a solution to the equation​
guajiro [1.7K]

Answer:

x = 1 is not a solution to the equation

Step-by-step explanation:

2x + 4 = -3x - 2            x = 1

2(1) + 4 = -3(1) - 2

2 + 4 = -3 - 2

6 = -5 FALSE

5 0
3 years ago
Solve the inequality 2x&gt;30+5/4x
insens350 [35]

Answer:

Step-by-step explanation:

2x > 30+\frac{5}{4x} \\2x-\frac{5}{4x} > 30\\\frac{8x^2-5}{4x} > 30\\case~1\\if~x > 0\\8x^2-5 > 120x\\8x^2-120x > 5\\x^2-15x > \frac{5}{8} \\adding~(-\frac{15}{2} )^2~to~both~sides\\(x-\frac{15}{2} )^2 > \frac{5}{8}+\frac{225}{4} \\(x-\frac{15}{2} )^2 > \frac{455}{8} \\x-\frac{15}{2} < -\sqrt{\frac{455}{8} }  \\x < \frac{15}{2}-\sqrt{\frac{455}{8} } \\or~x < 0\\rejected~as~x > 0

x-\frac{15}{2} > \sqrt{\frac{455}{8} } \\x > \frac{15}{2} +\sqrt{\frac{455}{8} }

case~2

if~x < 0\\8x^2-5 < 120x\\8x^2-120x < 5\\x^2-15x < \frac{5}{8} \\adding~(-\frac{15}{2} )^2\\(x-\frac{15}{2} )^2 < \frac{5}{8} +(-\frac{15}{2} )^2\\|x-\frac{15}{2} | < \frac{5+450}{8} \\-\sqrt{\frac{455}{8} } < x-\frac{15}{2} < \sqrt{\frac{455}{8} } \\\frac{15}{2} -\sqrt{\frac{455}{8} } < x < \frac{15}{2} +\sqrt{\frac{455}{8} } \\but~x < 0\\7.5-\sqrt{\frac{455}{8} } < x < 0

8 0
1 year ago
What happens to the volume of a cylinder when the radius is doubled?
wlad13 [49]
When the radius is doubled, the volume of a cylinder quadruple

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3 years ago
Read 2 more answers
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