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babymother [125]
1 year ago
6

Help help help help help just need answer

Mathematics
1 answer:
kirza4 [7]1 year ago
5 0

Answer:

25 miles

Step-by-step explanation:

2 inches represents 10 miles ( divide both parts by 2 )

1 inch represents 5 miles , then

5 inches represents 5 × 5 = 25 miles

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Find MN<br><br> LM = 3y + 4<br> MN = 7y + 9<br> LN = 143
ahrayia [7]

Answer:

B. 100

Step-by-step explanation:

3y+4+7y+9=143

10x+13=143  143-13=130

10x=130 divide both sides by 10 130/10= 13 x=13

MN=7(13)=91+9=100

LN=3(13)=39+4=43

100+43

6 0
3 years ago
What inequality represents the solution of 0.25x+4y-4&gt;0.75x+12 in terms of y?
matrenka [14]
Show me the choices...................
3 0
3 years ago
Use the commutative property to rewrite the following expression.<br> -16 · y
Y_Kistochka [10]
Commutative property of multiplication is just mixing up the order but the answer stays the same.
Examples: 4 + 5 + 6 = 6 + 4 + 5 ; (a)(d) = (d)(a) ;

Answer:
(-16)(y) or/and (y)(-16)
7 0
3 years ago
Agan Interior Design provides home and office decorating assistance to its customers. In normal operation, an average of 2.3 cus
likoan [24]

Given Information:

Average customer arrival = λ =2.3 customers/hour

Average consultant time1 = μ  = 8 minutes/customer

Average consultant time2 = μ  = 10 minutes/customer

Cost of consultants service = $16

Cost of customer waiting time = $25

Required  Information:

Use one consultant with an average service time of 8 minutes/customer or use two consultants, each with average service time of 10 minutes/customer ?

Answer:

it is recommended to use one consultant with an average service time of 8 minutes/customer.

Step-by-step explanation:

Convert the average consultant time to hours/customer

Average consultant time1 = μ  = 60/8 = 7.5 hours/customer

Average consultant time2 = μ  = 60/10 = 6 hours/customer

Single consultant queuing model:

Calculations for one consultant

Average no. of customers waiting for service = Lq = λ²/μ(μ-λ)

Average no. of customers waiting for service = Lq = (2.3)²/7.5(7.5 - 2.5)

Average no. of customers waiting for service = Lq = 0.1356

Average no. of customers in the system = L = Lq + λ/μ

Average no. of customers in the system = L = 0.1356 + 2.3/7.5

Average no. of customers in the system = L = 0.442

Total cost = (customer waiting time cost)*L + consultant service cost

Total cost = $25*0.442 + $16

Total cost = $27.05

Multi consultant queuing model:

Calculations for two consultants

Average no. of customers waiting for service = Lq = ((λ/μ)^k(λμ)/(k -1)(kμ - λ))*P₀

Where k = 2 is the number of consultants and P₀ is the probability that all of the k consultants are idle. The value of P₀  can be found in the tables with λ/μ = 2.3/6 = 0.38 and k = 2,  P₀ ≅ 0.685

Average no. of customers waiting for service = Lq = (2.3/6)²(2.3*6)/(2-1)(2*6 - 2.3)*0.685

Average no. of customers waiting for service = Lq = 0.1431

Average no. of customers in the system = L = Lq + λ/μ

Average no. of customers in the system = L = 0.1431 + 2.3/6

Average no. of customers in the system = L = 0.5264

Total cost = (customer waiting time cost)*L + consultant service cost

Total cost = $25*0.5264 + ($16)*2 (since there are 2 consultants now)

Total cost = $45.16

Conclusion:

Therefore, it is recommended to use one consultant with an average service time of 8 minutes per customer since the total cost is less than the other option.

3 0
3 years ago
#4 !!!!!!!<br> Quick like right now please !
Taya2010 [7]
7(90) + 7(8). The answer is 686.
3 0
3 years ago
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