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Natali5045456 [20]
2 years ago
15

kathy uses a 1/2 cup of milk with every bowl of her favorite cereal if there are only 3 3/5 cups of milk left, then how many bow

ls of cereal would kathy have?
Mathematics
1 answer:
Murrr4er [49]2 years ago
6 0

Taking a quotient, we will see that she can make 7 bowls of cereal (and some leftover milk).

<h3>How many bowls of cereal would kathy have?</h3>

We know that for each bowl, she needs 1/2 cups of milk.

And we also know that she has a total of (3 + 3/5) cups of milk.

To know how many bowls she can make, we need to take the quotient between the total that she has and the amount that she needs for each bowl:

(3 + 3/5)/(1/2)

We can rewrite the total as:

3 + 3/5 = 15/5 + 3/5 = 18/5

Then the quotient becomes:

(18/5)/(1/2) = (18/5)*2 = 36/5 = 35/5 + 1/5 = 7 + 1/5

So she can make 7 bowls of cereal (and some leftover milk).

If you want to learn more about quotients:

brainly.com/question/629998

#SPJ1

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Jada's sister works in a furniture store.
Bingel [31]

Answer:

1) $16.35

2) 75%

3) $245  

Step-by-step explanation:

1) Jada earns = $15 per hour

  9% increase = 15 * 9/100 = $1.35

  Increased Jada's pay = 15+1.35 = $16.35

2) Markup = selling price - cost= $350 - 200= $150

   Markup % = \frac{sale price - cost }{cost}*100 \

                      = \frac{150}{200}*100 = 75%

3) Jada's sister commission is 3.5% of $7000

          = \frac{3.5}{100}* 7000

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5 0
3 years ago
The Pew Internet and American Life Project reported Wednesday, April 18th that two- thirds (67%) of young adults with profiles o
dlinn [17]

Answer:

At 5% significance level, larger proportion of military personnel students protect their profiles on social-networking sites than young adults with profiles on social-networking sites.

Step-by-step explanation:

let p be the proportion of military personnel students who restrict access to their profiles. Then null and alternative hypotheses are:

H_{0}: p=0.67 (67%)

H_{a}: p>0.67

We need to calculate z-statistic of sample proportion:

z=\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } } where

  • p(s) is the sample proportion of military students who restrict access to their profiles ( \frac{78}{100} =0.78)
  • p is the proportion assumed under null hypothesis. (0.67)
  • N is the sample size (100)

Then z=\frac{0.78-0.67}{\sqrt{\frac{0.67*0.33}{100} } } ≈ 2.34

The corresponding p-value is 0.0096. Since 0.0096<0.05 (significance level) we can reject the null hypothesis and conclude at 5% significance level that larger proportion of military personnel students protect their profiles on social-networking sites than young adults with profiles on social-networking sites.

3 0
3 years ago
Solve the system of equations by ELIMINATION.
Dafna1 [17]

Step-by-step explanation:

4x + 2y = 10 --------(1)

2x + 3y = 33 -----------(2)

Multiply 2 with eq. (1) and 4 with eq. (2)

8x + 4y = 20 ____________(3)

8x + 12y = 132 ______(4)

Subtracting (3) from (4),

8x + 4y = 20

- 8x -12y = -132

----------------------

0 -8y = -112

y = 112/8

y = 4 is the answer.

Putting the vakue of y in eq. (2),

2x + 12 = 33

2x = 33-12

2x = 21

x = 21/2 is the answer.

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A man wants to paint his room with an area of 515 square feet. He mixses the following paints to make a shade of green
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About 3 gallons of blue paint will be needed because if you add 175+175 it equals 350 and then add another 175 it equals 525. 
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Plz help I'm really bad at these
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Y = mx + b, where m = slope = rise/run and b, the y intercept value

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4 years ago
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