Answer:
Correct answer: F. graph F or x ∈ |-5 ; 5| (including endpoints)
Step-by-step explanation:
Let us first define the absolute value:
| x | = 1. { x with condition x ≥ 0 }
or 2. { - x with condition x < 0 }
This is a linear inequality
1. x ≤ 5 ∧ x ≥ 0 ⇒ 0 ≤ x ≤ 5 or interval x ∈ |0 ; 5| (including endpoints)
2. - x ≤ 5 when we multiply both sides of the equation by -1 we get:
x ≥ -5 ∧ x < 0 ⇒ -5 ≤ x < 0 or interval x ∈ |-5 ; 0) (including -5)
The solution to this linear inequality is the union of these two intervals:
x ∈ |-5 ; 0) ∪ |0 ; 5| ⇒ x ∈ |-5 ; 5| (including endpoints)
x ∈ |-5 ; 5| (including endpoints)
God is with you!!!
Answer:
A. (x−2y)(y−3x)
=(x+−2y)(y+−3x)
=(x)(y)+(x)(−3x)+(−2y)(y)+(−2y)(−3x)
=xy−3x2−2y2+6xy
=−3x2+7xy−2y2
B. (2p+3)(p2−4p−7)
=(2p+3)(p2+−4p+−7)
=(2p)(p2)+(2p)(−4p)+(2p)(−7)+(3)(p2)+(3)(−4p)+(3)(−7)
=2p3−8p2−14p+3p2−12p−21
=2p3−5p2−26p−21
Hope it helps
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Thank you
600 - 20w > 300
-20w > 300 - 600
-20w > - 300
20w < 300
w < 300/20
w < 15
Therefore, Jenny can withdraw $20 from her account for 14 weeks
Answer:
I like ya cut g
Step-by-step explanation:
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