All categories

2 years ago

What is the range of function g if g (x) = f(x) + 3?

Mathematics

1 answer:

masya89 [10]2 years ago

7 0

I think it is D, hope it helps

You might be interested in

To find the value of the following expression, which task should be completed second? 7 × 22 + (8 - 2) ÷ 3

lina2011 [118]

Answer: 7 x 22

The law of BIDMAS, or PEMDAS, or BODMAS, whatever you call it, states first brackets (parentheses), indices (exponents, orders), multiplication or division, addition, subtraction.

So first you would do the brackets (8 - 2), and then you should do the multiplication 7 x 22. I think.

3 0

4 years ago

PLEASEE HELPP HELPP IMMA FAIL

djverab [1.8K]

the photo is not oploding i cant see

7 0

3 years ago

Read 2 more answers

Evaluate the following expression: 082

Sauron [17]

This for points.

Nanskw

7 0

3 years ago

Simplify 3×+1(2×-1)2-1(6×)

trasher [3.6K]

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Hi my lil bunny!

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

Answer = $\boxed {x - 2}$

$3x +1(2x-1)2-1(6x)$

= $\boxed {3x + 1 . ( 2x - 1 ) . 2 - 1 (6x) = x - 2}$

Steps :

$3x + 1 . (2x - 1) . 2 - 1 . (6x)$

Remove the parentheses : $(a) = a$

$= 3x + 1 * (2x- 1) * 2 - 1 * 6x$

Multiply the numbers : $1 * 2 = 2$

$= 3x + 2 ( 2x - 1 ) * 6x$

Multiply the numbers : $1 * 6 = 6$

$= 3x + 2 ( 2x - 1 ) -6x$

Expand: $2 (2x - 1) : 4x - 2$

$2 ( 2x - 1 )$

Apply the distributive law : $a (b - c) = ab - ac$

$a = 2, b = 2x, c = 1 \\= 2 * 2x - 2 * 1$

Simplify $2 * 2x - 2 * 1 : 4x - 2$

= $= 4x - 2$

$= 3x + 4x - 2 - 6x$

Simplify $3x + 4x - 2 - 6x : x - 2$

= $x - 2$

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Have a great day/night!

❀*May*❀

7 0

3 years ago

Find the value of the following expression:

Misha Larkins [42]

$(2^8*3^{-5}*6^0)^{-2}*( \cfrac{3^{-2}}{2^3} )^4*2^{28}\\ \\\\ = (\cfrac{2^8}{3^5}*1)^{-2} *( \cfrac{1}{3^2*2^3} )^4*2^{28}\\\\\\=( \cfrac{3^5}{2^8} )^2* \cfrac{1^4}{3^{2*4}*2^{3*4}} *2^{28}\\\\\\= \cfrac{3^{5*2}}{2^{8*2}} * \cfrac{1}{3^8*2^{12}} *2^{28}\\\\\\=\cfrac{3^{10}}{2^{16}} * \cfrac{2^{28}}{3^8*2^{12}}\\\\\\= \cfrac{3^{10}*2^{28}}{3^8*2^{16+12}} \\\\\\=\cfrac{3^{10}*2^{28}}{3^8*2^{28}} \\\\=3^{10-8}*2^{28-28}\\\\=3^2*2^0\\\\=9*1\\\\=9$

3 0

4 years ago

Read 2 more answers