Let numbers be x and y
ATQ
Adding both



Now putting value in eq(2)



B. is true. 15·(–5) > 23·(–12).
15·(-5)=-75.
23·(-12)=-276.
-75 > -276
Answer:
f(-2) = -1
Step-by-step explanation:
One way of doing this is to substitute -2 for x in every place where x shows up:
f(x) = 4x + 3x^2 − 5 → f(-2) = 4(-2) + 3(-2)^2 − 5
→ f(-2) = -8 + 3(4) - 5, or f(-2) = 4 - 5, or f(-2) = -1
Not sure why such an old question is showing up on my feed...
Anyway, let

and

. Then we want to find the exact value of

.
Use the angle difference identity:

and right away we find

. By the Pythagorean theorem, we also find

. (Actually, this could potentially be negative, but let's assume all angles are in the first quadrant for convenience.)
Meanwhile, if

, then (by Pythagorean theorem)

, so

. And from this,

.
So,
-1, because the equation for the slope is y2-y1/x2-x1. So let's bring the y value in the second set of point, which is 20, and bring the first y value in the first set of points, which is 5. 20-5 is 15. Now let's subtract the x values. So the second x from the second parentheses x value is -7, and the first x value from the first parentheses is 8. -7-8 is -15. Now we have this division equation, 15/-15, which is -1. So therefore, the slope of the line will be -1.