In the parallelogram ABCD, join BD.
Consider the triangle Δ ABD.
It is given that AB > AD.
Since, in a triangle, angle opposite to longer side is larger, we have,
∠ ADB > ∠ ABD. --- (1)
Also, AB || DC and BD is a transversal.
Therefore,
∠ ABD = ∠ BDC
Substitute in (1), we get,
∠ ADB > ∠ BDC.
Answer: Answer for figure one is origin (0,0)
Answer for figure two is (2,4) /
Step-by-step explanation:
a) Here we can see that given graph is the equation of cubic function which is
f(-x) = -f(x) that is given function is odd then rotational symmetry point is origin always ,therefore point of rotational symmetry is origin (0,0)
b) The rotational symmetry of an ellipse is 180 degrees about the center of the ellipse .
And here the center of given ellipse is (2,4) ,therefore its rotational symmetry is about (2,4) That is if we rotate the given ellipse 180 degrees about (2,4) it will be at its original position.
A quadratic function is one of the form f(x) = ax2 + bx + c, where a, b, and c are numbers with a not equal to zero. The graph of a quadratic function is a curve called a parabola. ... A parabola intersects its axis of symmetry at a point called the vertex of the parabola. You know that two points determine a line.
Answer: It =5
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