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Mathematics

1 answer:

Juli2301 [7.4K]4 years ago

6 0

It's 3.2 units
hope it's helps

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Maria drove to a business appointment at 50mph in the morning. Her average speed on the return trip in the afternoon was 40 mph.

MakcuM [25]

Answer:

Distance to appointment point = 5 miles

Step-by-step explanation:

Let s be the distance to the appointment point,

We have Maria drove to a business appointment at 50mph in the morning.

Time taken in the morning

$t_m=\frac{s}{50}=0.02s$

Her average speed on the return trip in the afternoon was 40 mph.

Time taken in the afternoon

$t_a=\frac{s}{40}=0.025s$

Given that the return trip took 1/4hr longer because of traffic.

That is

$t_a-t_m=\frac{1}{4}hr=0.025hr$

Substituting

$t_a-t_m=0.025hr\\\\0.025s-0.02s=0.025\\\\s=5miles$

Distance to appointment point = 5 miles

7 0

3 years ago

Show a way to count from 170 to 410 using tens and hundreds. circle at least 1 benchmark number

Anastasy [175]

Benchmark are numbers that are used as standards to which the rest of the data is compared to. When counting numbers using a number line, the benchmark numbers are the intervals written on the axis. For benchmark numbers of 10, the number line on top of the attached picture is shown. Starting from 170, the tick marks are added by 10, such that the next numbers are 180, 190, 200, and so on and so forth. When you want to find 410, just find the benchmark number 410.

The same applies to benchmark numbers in intervals of 100. If you want to find 170, used the benchmark numbers 100 and 200. Then, you estimate at which point represents 170. For 410, you base on the benchmark numbers 400 and 500.