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abruzzese [7]
3 years ago
11

PLEASE HELLLLLPPPPPPP

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
6 0
It's 3.2 units
hope it's helps

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GREYUIT [131]

Answer:

Step-by-step explanation:

1.

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3 years ago
Which is equivalent to (3/125)*?
Viktor [21]

Answer:

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5 0
3 years ago
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The intensity of a light source at a distance is directly proportional to the strength of the source and inversely proportional
jolli1 [7]

Answer:

x=\frac{16}{\sqrt[3]{2}+1 }

Step-by-step explanation:

Q= illumination

I = intensity

Q= I/d^2

Q_total = \frac{I_1}{d_1^2}+\frac{I_2}{d_2^2}

= \frac{I}{x^2}+\frac{2I}{(16-x)^2}

now Q' = 0

⇒I{-\frac{2}{x^3}}+\frac{4}{(16-x)^3}

x=\frac{16}{\sqrt[3]{2}+1 }

[/tex]\frac{1}{x^3} = \frac{2}{(16-x)^3}

x=\frac{16}{\sqrt[3]{2}+1 }

is the required point

5 0
3 years ago
Please help me this question​
ANTONII [103]

Answer:

0

Step-by-step explanation:

bcoz 2^5 X 9²=2592

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Solve for the variable r in this equation: <br><br> s = 2_rh
svp [43]
I hope this helps you



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3 0
3 years ago
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