Answer:
66 ≤ f ≤100
Explanation
Mean= ( Σ x ) / n
Mean= sum of scores/ number of subject she took
Now, she already too 3 subject which sum is 85+83+86=254
Now we need to know range of score for her to have (grade) a mark between 80 and 89
Now let take the lower limit mean=80
The lowest score she can get is
Mean = ( Σx) / n
80=(85+83+86+f)/4
80×4= 254+f
Therefore, f= 320-254=66
Therefore the minimum score she can have to have a B is 66.
Then, let take the upper limit mean 89. i.e the maximum she can have so that she don't have an A grade.
Mean = ( Σx) / n
89=( 83+85+86+f)/4
89×4= 254+f
f= 356-254
f=102.
Therefore this shows that she cannot have an A grade in the exam. The maximum score for the exam is 100.
There the range of score is 66 ≤ f ≤100 to have a B grade
66 ≤ f ≤100 answer
Since she cannot score 102 in the examination.
For 9 in standees form just write the regular number
Answer:
30 more
Step-by-step explanation:
hope it helps friend.
Answer:
Answer is 100 sq m
Step-by-step explanation:
A = 
A = 
A = 100 sq m
HOPE IT HELPS
<u><em>(FROM CROSS)</em></u>
Answer:
(-3, 4)
Step-by-step explanation:
let the point P(x, y)
x = (5/7 × (-1+8)) + (-8)
= (5/7 × 7) -8 = 5-8 = -3
y = (5/7 × (8+6)) + (-6)
= (5/7 × 14) -6 = 10-6 = 4
so, P => (-3 , 4)