Answer:
333/3 = 111 yards Joey walked
4.
The equation we have is:
To solve for "a", we want to isolate it in one side.
For this. we can start by multiplying each side by 5. This will make the denominator to cancel out:
Now, we can divide both sides by 8, which will cancel the coefficient 8 multiplying "a":
And that is the answer to 4.
Answer:
One number sentence shows the distributive property of multiplication over addition. ... (5 + 4) × 3 = (5 × 3) + (4 × 3) is an example of the distributive property. (5 − 4) × 3 = 1 × 3. 1 × 3 is not equal to (1 × 3) − (1 × 3).
Step-by-step explanation:
A
4^2*11^2= 44
that is x I don't know about the rest of the problem.
Answer:
Q(t) = Q_o*e^(-0.000120968*t)
Step-by-step explanation:
Given:
- The ODE of the life of Carbon-14:
Q' = -r*Q
- The initial conditions Q(0) = Q_o
- Carbon isotope reaches its half life in t = 5730 yrs
Find:
The expression for Q(t).
Solution:
- Assuming Q(t) satisfies:
Q' = -r*Q
- Separate variables:
dQ / Q = -r .dt
- Integrate both sides:
Ln(Q) = -r*t + C
- Make the relation for Q:
Q = C*e^(-r*t)
- Using initial conditions given:
Q(0) = Q_o
Q_o = C*e^(-r*0)
C = Q_o
- The relation is:
Q(t) = Q_o*e^(-r*t)
- We are also given that the half life of carbon is t = 5730 years:
Q_o / 2 = Q_o*e^(-5730*r)
-Ln(0.5) = 5730*r
r = -Ln(0.5)/5730
r = 0.000120968
- Hence, our expression for Q(t) would be:
Q(t) = Q_o*e^(-0.000120968*t)
