We have a "rectangular" double loop, meaning that both loops go to completion.
So there are 3*4=12 executions of t:=t+ij.
Assuming two operatiions per execution of the innermost loop, (i.e. ignoring the implied additions in increment of subscripts), we have 12*2=24 operations in all.
Here the number of operations (+ or *) is exactly known (=24).
Big-O estimates are used for cases with a varying scale of operations, governed by a variable (usually n) to indicate the sensitivity of the number of operations relative to a change in the size of n.
Here we do not have a scale, nor n is defined. The number of operations is constant and known at 24. So a variable is required to find the big-O estimate.
Answer: I really don’t know lol
Step-by-step explanation:
What it is side ways i can help sory
Answer:
Step-by-step explanation:
Mr. Rives' rotating sprinkler waters his lawn up to a radius of 7 feet. The formula for determining the area of a circle is expressed as
Area = πr²
Where
π is a constant whose value is 3.14.
r represents the radius if the circle.
The area covered by one of Mr. Rives' rotating sprinkler would be
3.14 × 7² = 3.14 × 49 = 153.86ft²
Therefore, the maximum area of lawn that two sprinklers can cover would be
153.86 × 2 = 307.72 ft²
Answer:
It takes 70 minutes for 9 team members (painting 60 sq ft per minute) to paint a 4200 sq ft wall.
Step-by-step explanation:
According to the situation the calculation is shown below:-
= 
= 240 sq ft each member of the team in 36 minutes
= 
= 6.67 sq ft each member of the team within 1 minute
= 60 sq ft for every 9 team members in one minute
= 
= 70 minutes (or 1 hour and 10 minutes)
Hence, the 70 minutes is taken for 9 team members
