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Alik [6]
2 years ago
12

The population parameter value and the point estimate differ because a sample is not a census of the entire population, but it i

s being used to develop the _____. Group of answer choices population parameter point estimate population mean standard error
Mathematics
1 answer:
Assoli18 [71]2 years ago
3 0

The population parameter value and the point estimate differ because a sample is not census of the entire population,  but it is being used to develop the point estimate.

According to the question,

The population parameter value and the point estimate differ because a sample is not census of the entire population,  but it is being used to develop the point estimate.

The sample proportion p, is a point estimate of the population proportion.

Hence, the correct answer is point estimate. Thus, the population parameter value and the point estimate differ because a sample is not census of the entire population,  but it is being used to develop the point estimate.

Learn more about population parameter here

brainly.com/question/3640262

#SPJ4

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Flura [38]

Answer:

y = -1

Step-by-step explanation:

3(2) + y = 5

6 + y = 5

-6

y = 5 -6

y = -1

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What is the determinant of A = [ -2 2 -5 4 -1 -2 1 3 -5]
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Answer:

-51

Step-by-step explanation:

\begin{vmatrix}-2&2&-5\\4&-1&-2\\1&3&-5\end{vmatrix}=\\=\mathsf{-10-4-60-5+40-12}=\\=\mathsf{-91+40}=\\=\mathsf{-51}

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6 0
3 years ago
Refer to the following distribution of commissions:______. Monthly Commissions Class Frequencies $600 up to $800 3 $800 up to 1,
blsea [12.9K]

Answer:

 the midpoint of the class with the greatest frequency 1500

Step-by-step explanation:

The illustration of the dataset given can be well represented in a table format as shown below.

Class                      Frequency                     Relative Frequency

$600 - $800                   3                              \mathbf{   \dfrac{3}{120} = 0.025}

$800 - $1000                  7                              \mathbf{   \dfrac{7}{120} = 0.059}

$1000 - $1200                11                              \mathbf{   \dfrac{11}{120} = 0.092}

$1200 - $1400                22                             \mathbf{   \dfrac{22}{120} = 0.183}

$1400 - $1600                40                            \mathbf{   \dfrac{40}{120} = 0.333}

$1600 - $1800                 24                            \mathbf{   \dfrac{24}{120} = 0.2}

$1800 - $2000                 9                            \mathbf{   \dfrac{9}{120} = 0.075}

$2000 - $2200                4                             \mathbf{   \dfrac{4}{120} = 0.033}

Total                               120                                           1

Therefore, the midpoint of the class with the greatest frequency is between  $1400 - $1600  since the frequency 40 happens to be the greatest frequency

The midpoint =\dfrac{upper \ limit + \ lower \ limit}{2}

The midpoint =\dfrac{1400+1600}{2}

= 1500

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Answer correct for brainliest and a thanks ! Don't answer if you don't know it please :) and it's blurry some so just zoom in !
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The percent of variation is 85.1%.  If you enter the numbers into a calculator and store the regression equation, it will be the r^2 value when calculated.
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