Answer:
x is -4.
TRS is 89.
Step-by-step explanation:
So we know that QR bisects QRS. By the definition of an angle bisector, this means that the adjacent angles are equivalent. In other words:

We are told that QRS is (9x+214). QRS is the sum of QRT and TRS. Thus:

And since we now that QRT and TRS are equivalent, substitute:

Combine like terms:

Substitute them for their equations:

Now, solve for x. On the right, distribute:

Add 18x to both sides:

Subtract 214 from both sides:

Divide both sides by 27:

So, the value of x is -4.
To find TRS, substitute x=-4 back into the equation. So:

Multiply and add:

And we're done!