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jasenka [17]
2 years ago
5

Answer urgent please!!

Mathematics
1 answer:
butalik [34]2 years ago
4 0

Answer:

  • 15

Step-by-step explanation:

u=5i-j\\\\v=3i+j\\\\w=i+4j\\

v+w

3i+j+i+4j\\\\4i+5j\\\\u*(v+w)\\\\(5i-j)(4i+5j)\\\\20-5\\\\\boxed{15}

~

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PLEASE HELP ME!!!
Lady_Fox [76]

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<h2> I am not so good at drawing .</h2><h3>BE = 3.6</h3>

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3 years ago
Consider that ΔQRS is similar to ΔLMN and the measure of ∠N is 42°. What is the measure of ∠S? A) 42° B) 48° C) 56° D) 58°
Veseljchak [2.6K]

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The answer is A) 42°

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7 0
3 years ago
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What is the value of 3 to the power 2 over 3 to the power 4? A. 1 over 81 B. 1 over 27 C. 1 over 9 D. 1 over 3
rodikova [14]
One way you could solve this is to just multiply the top and bottom out so that you get 9/81, reducing it by 9/9 to get 1/9 or option C.
Another way would be to do 3^{(2-4)} since dividing numbers with exponents would be subtracting the bottom exponent from the top exponent, provided that the base number (in this case 3) is the same for both. For this method, you would get 3^{-2}, which is equal to 1/9 or .1 repeating, the same answer that you'd get with the first method.
6 0
3 years ago
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Since the slope of a vertical line is undefined, is it possible ofr vertical lines to be parallel?
ikadub [295]

Yes, because if you have x=5 and x=10 they are parallel lines to each other.

6 0
3 years ago
The supplement of an angle is 50 less than 3 times its complement, find the measure of the angle
Lelechka [254]

Answer:

20^{\circ}.

Step-by-step explanation:

Two angles are supplements of one another if their sum is 180^{\circ}.

Two angles are complements of one another if their sum is 90^{\circ}.

Let x^{\circ} be the measure of the angle in question.

The supplement of this angle would be (180 - x)^{\circ}.

The complement of this angle would be (90 - x)^{\circ}.

According to the question:

(180 - x) + 50 = 3\, (90 - x).

Solve this equation for x:

x = 20.

Thus, this angle would measure should 20^{\circ}.

The supplement of this angle would measure (180 - 20)^{\circ} = 160^{\circ}. The complement of this angle would measure (90 - 20)^{\circ} = 70^{\circ}.

Three times the complement of this angle would be 3 \times 70^{\circ} = 210^{\circ}, which is indeed 50^{\circ} greater than the supplement of this angle.

8 0
3 years ago
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