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Ksivusya [100]
2 years ago
5

30 A club of 12 people would like to choose people for the offices of president, a vice president, and a secretary. How many dif

ferent ways are there to select the officers so that only one person holds each office?
Mathematics
1 answer:
babunello [35]2 years ago
8 0

1320 different ways are there to select the officers so that only one person holds each office given that the club has 12 people who would like to choose people for the offices of president, a vice president, and a secretary. This can be obtained by using the formula of permutation.

<h3>How many different ways are there to select the officers so that only one person holds each office?</h3>

Total number of people in the club = 12

total number of positions = (president, vice president, secretary) = 3

From 12 people 3 people are taken at a time.

That is, using the formula for permutation we get,

ⁿPₓ = \frac{n!}{(n-x)!}

Here n = 12 and x = 3

P(12,3)= 12!/(12-3)! =12!/9! = 10×11×12 = 1320

Hence 1320 different ways are there to select the officers so that only one person holds each office given that the club has 12 people who would like to choose people for the offices of president, a vice president, and a secretary.

Learn more about permutation here:

brainly.com/question/1216161

#SPJ4

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