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2 years ago

Surface area= Volume = Help me please thanks

Mathematics

2 answers:

sleet_krkn [62]2 years ago

5 0

Answers
Surface area is 964 cm2
Volume is 1872 cm3

Step by step
Using L=length, w=width, h= height

Surface area is found by adding the area of all 6 sides. Area is found by multiplying L x W.
8x18 = 144 x2 sides = 288
18x13 = 234 x2 sides = 468
8x13 = 104 x2 sides = 208
Total all sides = 964

Volume of a rectangle is found by multiplying L x W x H
13 x 18 x 8
Volume is 1872 cm3

Vesna [10]2 years ago

4 0

Im am sorry but I don’t know

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3 years ago

Suppose that triangle TUV is an isosceles with the base VU.

vekshin1

Set them equal to each other and solve
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Plug it in
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3 years ago

Harry is riding a train that goes 70 miles an<br> hour. How far will he travel is 3.5 hours?

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2 years ago

Read 2 more answers

For the composite function, identify an inside function and an outside function and write the derivative with respect to x of th

alexira [117]

Answer:

The inner function is $h(x)=4x^2 + 8$ and the outer function is $g(x)=3x^5$ .

The derivative of the function is $\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4$ .

Step-by-step explanation:

A composite function can be written as $g(h(x))$ , where $h$ and $g$ are basic functions.

For the function $f(x)=3(4x^2+8)^5$ .

The inner function is the part we evaluate first. Frequently, we can identify the correct expression because it will appear within a grouping symbol one or more times in our composed function.

Here, we have $4x^2+8$ inside parentheses. So $h(x)=4x^2 + 8$ is the inner function and the outer function is $g(x)=3x^5$ .

The chain rule says:

$\frac{d}{dx}[f(g(x))]=f'(g(x))g'(x)$

It tells us how to differentiate composite functions.

The function $f(x)=3(4x^2+8)^5$ is the composition, $g(h(x))$ , of

outside function: $g(x)=3x^5$

inside function: $h(x)=4x^2 + 8$

The derivative of this is computed as

$\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=3\frac{d}{dx}\left(\left(4x^2+8\right)^5\right)\\\\\mathrm{Apply\:the\:chain\:rule}:\quad \frac{df\left(u\right)}{dx}=\frac{df}{du}\cdot \frac{du}{dx}\\f=u^5,\:\:u=\left(4x^2+8\right)\\\\3\frac{d}{du}\left(u^5\right)\frac{d}{dx}\left(4x^2+8\right)\\\\3\cdot \:5\left(4x^2+8\right)^4\cdot \:8x\\\\120x\left(4x^2+8\right)^4$

The derivative of the function is $\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4$ .

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