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3 years ago

What is radical 64/8 simplified

Mathematics

2 answers:

Luda [366]3 years ago

4 0

The answer is 8, because 64÷8= 8!simple

Sergeu [11.5K]3 years ago

3 0

Answer:

2^(6-3) = 2^3 = 8

Step-by-step explanation:

To simplify radical 64/8

We will express 64 and 8 in powers of 2

64 = 2×2×2×2×2×2= 2^6

8 = 2×2×2=2^3

From the law of indices,

a^5 / a^3 = a^ (5-3) = a^2

Applying this law of indices to the given radical,

64/8 = 2^6/ 2^3

= 2^(6-3)

= 2^3 = 8

Also, we can try another way. since

64 = 2×2×2×2×2×2= 2^6

8 = 2×2×2=2^3

64/8 = 2×2×2×2×2×2 / 2×2×2

2×2×2 cancels out 2×2×2 and

It remains 2×2×2 = 8

So which ever way we do it,

radical 64/8 simplified is 2^3 = 8

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3 years ago

The range of 16,23,55,64,49

miskamm [114]

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<em>Greatest number</em> → 64

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Now, we need to subtract 16 from 64.

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3 years ago

A highway department executive claims that the number of fatal accidents which occur in her state does not vary from month to mo

den301095 [7]

This question is incomplete, the complete question;

A highway department executive claims that the number of fatal accidents which occur in her state does not vary from month to month. The results of a study of 193 fatal accidents were recorded. Is there enough evidence to reject the highway department executive's claim about the distribution of fatal accidents between each month? Month Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec Fatal Accidents 11 13 22 11 15 29 15 9 13 15 22 18

Step 10 of 10 : State the conclusion of the hypothesis test at the 0.1 level of significance.

Answer: H₀ : The distribution of fatal accidents between each month is same

Step-by-step explanation:

H₀ : The distribution of fatal accidents between each month is same

H₁ : The distribution of fatal accidents between each month is different

Let the los be alpha 0.10

given data ;

Observed Expected

Mon Freq (Oi) Freq Ei (Oi-Ei)^2 /Ei

Jan 11 16.0833 1.606649

Feb 13 16.0833 0.591105

Mar 22 16.0833 2.176598

Apr 11 16.0833 1.606649

May 15 16.0833 0.072971

Jun 29 16.0833 10.373489

Jul 15 16.0833 0.072971

Aug 9 16.0833 3.119603

Sep 13 16.0833 0.591105

Oct 15 16.0833 0.072971

Nov 22 16.0833 2.176598

Dec 18 16.0833 0.228411

Total: 193 93 22.689119

Expected Freq ⇒ 193 / 12 = 16.08333

Test Statistic, x² : 22.6891

Num Categories: 12

Degrees of freedom: 12 - 1 = 11

Critical value X² : 24.725

P-Value: 0.0195

since Chi-square value < Chi-square critical value

and P-value > alpha 0.01 so we accept H₀

Therefore we conclude that the distribution of fatal accidents between each month is same

7 0

3 years ago