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kobusy [5.1K]
3 years ago
15

The letters 's', 't', 'u', 'd', 'y', 'i', 's', 'l', 'a', 'n', 'd' are placed in a bag. one letter is randomly selected from the

bag. what is the probability the letter selected is a consonant? (note: count the letter 'y' as a vowel.)
Mathematics
1 answer:
Aleks [24]3 years ago
3 0

Answer:

<em><u>7/11</u></em>

Step-by-step explanation:

There are 11 letters in 'S', 'T', 'U', 'D', 'Y', 'I', 'S', 'L', 'A', 'N', 'D', so there are 11 letters in the bag.

There are 7 consonants in the bag.

So, the probability of selecting a consonant is 7 out of 11, or 7/11

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Problem 2
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x = [ 8 +/- sqrt (60)]/2                            Break 60 into 4 * 15 
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The Knowles/Armitage (KA) group at Merrill Lynch advises clients on how to create a diversified investment portfolio. One of the
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jan, mya, and Sara ran a total of 64 miles last week. jan and mya ran the same number of miles. Sara ran 8 less miles than mya.
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So,

We'll just use A to represent both Jan and Mya's miles, since they ran the same number.

We have the equations:
1. Jan (J) = Mya (M)
2. Sara (S) = M - 8
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J = M
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We'll just use A to represent both J and M.

S = M - 8

We'll use Elimination by Substitution.
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Since
A = J
and
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Substitute
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Check
24 + 24 + 16 = 64
64 = 64 This checks.

So,
J = 24
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3 years ago
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