Problem 1
Do you know what a complex number is? If you do not, you can get an answer but not one you will like much.
(3x)^2 + 27 = 0 remove the brackets. Remember to square what's inside the brackets.
9x^2 + 27 = 0 Divide both terms by 9
9x^2/9 + 27/9 = 0
x^2 + 3 = 0 Subtract 3 from both sides.
x^2 = -3 Take the square root from both sides.
x = sqrt(-3) but the square root of - 3 = 3i
x = i*sqrt(3)
Problem 2
x^ - 8x + 1 = 0
a = 1
b = - 8
c = 1
x = [- -8 +/- sqrt(b^2 - 4*a*c) ]/(2*a) Quadratic formula
x = [ 8 +/- sqrt( (-8)^2 - 4(1*1)]/2 Substitute Givens and combine
x = [ 8 +/- sqrt( 64 - 4 )] /2 Subtract 4
x = [ 8 +/- sqrt (60)]/2 Break 60 into 4 * 15
x = [ 8 +/- sqrt (4*15)]/2 Notice 4 is a perfect square. sqrt4 = 2
x = [ 8 +/- 2*sqrt(15)] / 2 Divide through by 2
x = 8/2 +/- sqrt (15)
x = 4 +/- sqrt(15) the twos were gone
Answer:
D and E
Step-by-step explanation:
27 and 50 are greater than 20. The scale factor is more than 1, so the answer(s) have to be more than 1.
Answer:
900cm^2
Step-by-step explanation:
24, 10, 30 in half= 12, 5, 15 so, 12*5*15=900cm^2
Answer:
See the attached file for the answers.
Step-by-step explanation:
See the attached file for the explanation
So,
We'll just use A to represent both Jan and Mya's miles, since they ran the same number.
We have the equations:
1. Jan (J) = Mya (M)
2. Sara (S) = M - 8
3. 2A + S = 64
J = M
S = M - 8
We'll just use A to represent both J and M.
S = M - 8
We'll use Elimination by Substitution.
2A + A - 8 = 64
Collect Like Terms
3A - 8 = 64
Add 8 to both sides
3A = 72
Divide both sides by 3
A = 24
Since
A = J
and
A = M
and
J = M
then
J = 24
M = 24
Substitute
S = 24 - 8
S = 16
Check
24 + 24 + 16 = 64
64 = 64 This checks.
So,
J = 24
M = 24
S = 16