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vovangra [49]
3 years ago
13

Help me, please. Please also explain to me why you picked your answer.

Mathematics
2 answers:
Shkiper50 [21]3 years ago
4 0

Answer: Lower left corner  \frac{29}{18+29} \times 100

We have 29 people who chose fishing out of 18+29 people who filled out the survey. We don't use 60 because not everyone filled out the survey, and we're only focusing on survey participants. The "times 100" at the end will move the decimal point 2 spots to the right, and convert it to percent form.

For example, if you had 2 people who liked fishing out of 8 total then 2/8 = 0.25 = 25% of the people like fishing.

balandron [24]3 years ago
4 0

Answer:it's C) 29×100/18+29

Step-by-step explanation:

For the percentage, we need the total number of boys who completed the survey which is 18+29. Again, the number of boys who chose fishing is 29. So, we should divide 29 by (18+29) & multiply 100c with it in order to get the percentage .

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What is the distance between (-2 1/2,-3) and (1,-3
satela [25.4K]

Answer:

3\frac{1}{2}\ units

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

(-2\frac{1}{2},-3)\ and\ (1,-3)

Convert mixed number to an improper fraction

2\frac{1}{2}=\frac{2*2+1}{2}=\frac{5}{2}

so

we have

(-\frac{5}{2},-3)\ and\ (1,-3)

substitute the values in the formula

d=\sqrt{(-3+3)^{2}+(1+\frac{5}{2})^{2}}

d=\sqrt{(0)^{2}+(\frac{7}{2})^{2}}

d=\frac{7}{2}\ units

Convert to mixed number

\frac{7}{2}\ units=\frac{6}{2}+\frac{1}{2}=3\frac{1}{2}\ units

6 0
3 years ago
Read 2 more answers
A student's grades in the three tests in College Algebra are 85, 60, and 69. a) How many points does the student need on the fin
Anastaziya [24]

Answer:

(a) The student need 82 points on the final to average 74.

(b) The student must score 41 points on the final, assuming that the final carries double the weight.

Step-by-step explanation:

We are given that a student's grades in the three tests in College Algebra are 85, 60, and 69.

As we know that the formula for calculating the average of numbers is given by;

          Average (Mean)  =  \frac{\text{Sum of all values}}{\text{Number of observations}}

(a) Let the points student need on the final test to average 74 be 'x'.

So, Average of all four test  =  \frac{85+60+69+x}{4}

                     74 = \frac{85+60+69+x}{4}

                     74 = \frac{214+x}{4}

                     214+x =74 \times 4

                      x = 296-214

                        x=82

Hence, the student needs 82 points on the final to average 74.

(b) It is given that the final carries double the weight, this means that let the points student need on the final test to average 74 be '2x'.

So, Average of all four test  =  \frac{85+60+69+2x}{4}

                     74 = \frac{85+60+69+2x}{4}

                     74 = \frac{214+2x}{4}

                     214+2x =74 \times 4

                      2x = 296-214

                        x=\frac{82}{2} = 41

Hence, the student must score on the final 41 points, assuming that the final carries double the weight.

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<span>(a^2+b^2)^2
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