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Crank
2 years ago
9

Which recursive formula can be used to represent the sequence 2,6,10,14,18...?

Mathematics
1 answer:
12345 [234]2 years ago
8 0

Answer:

a(1) = 2

a(n) = a(n-1)+4

Step-by-step explanation:

Using the given arithmetic sequence,

a1 is 2

a2 is 6

a3 is 10

a4 is 14

a5 is 18

and to get from a1 to a2 you have to +4, to get from a2 to a3 you have to +4 and so on.

In a reclusive formula you need to find two pieces of information:

1. The first term of the sequence

2. The pattern rule to get any term from the term that comes before it

Using the given sequence, the first term is 2 and the rule to get any term from its previous term is +4.

So, putting that information in the form of a recursive formula will read as the following:

an+1 = an+4

a1 = 2, n is greater or equal to 1 (n is an interger)

Which can be rearranged to

a(1) = 2

a(n) = a(n-1)+4

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MrRissso [65]
<h2>Answer:</h2>

The correct answer is:   Option: A

A.   85, 78, 80, 108, 46, 66, 68, 82, 72, 68

<h2>Step-by-step explanation:</h2>

It is given that:

The whisker ranges from 66 to 85.

The box ranges from 68 to 82 with the vertical bar inside the box at 75.

  • Hence, the minimum value of the box plot is: 66
  • Maximum value of box plot is: 85

Also,

  • The first quartile or the lower quartile i.e. Q_1 is: 68
  • The middle quartile or median i.e. Q_2 is: 75
  • The upper quartile or third quartile i.e. Q_3 is: 82

Also, it is given that:

One dot mark above forty-six.

One dot mark above one hundred and eight.

A)

On arranging the data in increasing order after removing outliers 46 and 108 we have:

 66    68    68    72    78    80    82     85  

Hence, from this data we have:

Minimum value=66

maximum value=85

Q_1=68\\\\Q_2=75\\\\\\Q_3=81

As all the values matches the value defined.

Hence, this option is correct.

B)

On arranging the data in increasing order after removing 46 and 108 we have:

66    68    68    70   70   80    82     85

Hence, from this data we have:

Minimum value=66

maximum value=85

Q_1=68\\\\Q_2=70\\\\\\Q_3=81

As the value of Q_2=70\neq 75.

Hence, this option is incorrect.

C)

On arranging the data in increasing order after removing 46 and 108 we have:

66    68    72    78   80   80    82     85

Hence, from this data we have:

Minimum value=66

maximum value=85

Q_1=70\\\\Q_2=79\\\\\\Q_3=81

As the value of  Q_1,Q_2\ and Q_3 do not match.

Hence, this option is incorrect.

D)

On arranging the data in increasing order after removing 46 and 108 we have:

66    68    68    72   78   80    80     85

Hence, from this data we have:

Minimum value=66

maximum value=85

Q_1=68\\\\Q_2=79\\\\\\Q_3=80

As the value of  Q_3=80\neq 82 do not match.

Hence, this option is incorrect.

4 0
3 years ago
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The degree of the polynomial function f(x) is 3.
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We are given degree of the polynomial function = 3.

Because degree is 3, there should be three x-intercepts of the given graph of the polynomial.

We also given roots of the equation f(x)=0 are −2 , 0, and 3.

Therefore, x intercepts should be at:

(0,0), (-2,0) and (3,0).

<h3>In the given options third option shows x-intercepts at 0, -2 and 3.</h3><h3>Therefore, correct option is 3rd option.</h3>

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3 years ago
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Nimfa-mama [501]

Answer:

The correct option is (A) No real solution.

Step-by-step explanation:

The expression provided is a quadratic equation.

8x^{2}-10x+15=0

The roots of a quadratic equation are:

x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{ 2a }

Here,

a = 8

b = -10

c = 15

The conditions to determine real and complex roots are:

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Compute the value of b^{2}-4ac as follows:

b^{2}-4ac=(-10)^{2}-(4\times 8\times15)\\\\

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The equation has two complex roots.

Thus, the correct option is (A).

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Step-by-step explanation:

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