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Ilia_Sergeevich [38]
3 years ago
14

A 95% confidence interval for a population mean is determined to be 100 to 120. if the confidence coefficient is reduced to 0.90

, the interval for μ
Mathematics
1 answer:
Lerok [7]3 years ago
4 0
For 95% CI
x - 0.05s = 100
x + 0.05s = 120
Solve for x and s

The interval for u with 90% is 
x - 0.10s
and
x + 0.10s
Substitute x and s
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<h3>Answer:  Choice D.   (3j, 3k)  and (3/j, 3/k)</h3>

The slash indicates a fraction.

=============================================

Proof:

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Case (1): j > 0 and k > 0

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-----------------------

Case (2): j > 0 and k < 0

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Case (3): j < 0 and k > 0

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If k > 0, then 3k > 0 and 3/k > 0

Points (3j, 3k) and (3/j, 3/k) are in quadrant 3.

------------------------

Case (4): j < 0 and k < 0

If j < 0, then 3j < 0 and 3/j < 0

If k < 0, then 3k < 0 and 3/k < 0

Points (3j, 3k) and (3/j, 3/k) are in quadrant 4.

------------------------

For nonzero integers j and k, we've shown that Points (3j, 3k) and (3/j, 3/k) are in the same quadrant. This concludes the proof.

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