A = 1/2(15+7+15+7)(13)
A= 1/2(44)(13)
A = 286
answer
286
Answer:
5040 watts i think
Step-by-step explanation:
1440 X 3 = 4320 24 / 12 = 2
1440 / 2 = 720
4320 + 720 = 5040
Answer:
Step-by-step explanation:
From the given information:
The null and the alternative hypothesis can be well written as:


Given that:
n = 200
x = 135
Alpha ∝ = 0.05 level of significance
Then;
⇒ 
= 200 × 0.6 × (1 -0.6)
= 200 × 0.6 × 0.4
= 48 ≥ 10
The sample proportion 

= 0.675
The test statistics 


Z = 2.165
The P-value = P(Z > 2.165)
= 1 - P(Z < 2.165)
From the z tables
= 1 - 0.9848
= 0.0152
Reject the null hypothesis since P-Value is lesser than alpha. ( i.e. 0.0152 < 0.05).
Thus, there is enough evidence to conclude that the value of the population proportion is greater than 0.6
Step-by-step explanation:
Let a be the price of 1 adult ticket.
Let c be the price of 1 child ticket.
given,

as equation 1,
and

as equation 2.
Now we will solve for a and c using elimination method of simultaneous equations.
Now we multiply equation 2 by 2 to eliminate a and solve for c.

This new equation will be equation 3.
Now we will use equation 1 - equation 3 to eliminate a and solve for c.

Now substitute c into equation 2.

Therefore one adult ticket will cost $17.50 and one child ticket will cost $9.50.