All categories

2 years ago

True or false: the mayans wrote the digits in their numerals in a vertical format

Mathematics

1 answer:

svetlana [45]2 years ago

6 0

Answer:

True

Step-by-step explanation:

You might be interested in

Which triangles could not be similar to triangle ABC ?

kenny6666 [7]

Answer:

trapizoids

Step-by-step explanation:

4 0

3 years ago

Work out the size of the angle marked X. Give your answer correct to 1 decimal place.

Maurinko [17]

Answer:

41.8°

Step-by-step explanation:

We solve using the Trigonometric function of Sine

Hypotenuse = 15cm

x = θ

Opposite = 10cm

sin θ = Opposite/Hypotenuse

sin θ = 10/15

θ = arc sin ( 10/15)

θ = 41.810314896°

θ = Approximately to 1 decimal place = 41.8°

Therefore, x = θ = 41.8°

5 0

3 years ago

George paid a total of $985 to rent a storage unit.

kondaur [170]

Answer:

290 + 5m = 985

Step-by-step explanation:

Given information:

Initial payment = $290
Total payment = $985
Extra amount each month = m
Length of rental = 5 months

From the given information, we can create the following equation:

Initial payment plus extra amount each month for 5 months equals total payment.

⇒ 290 + 5m = 985

To solve the equation:

Subtract 290 from both sides:

⇒ 290 + 5m - 290 = 985 - 290

⇒ 5m = 695

Divide both sides by 5:

⇒ 5m ÷ 5 = 695 ÷ 5

⇒ m = 139

Therefore, the extra amount George paid each month was $139.

5 0

2 years ago

Read 2 more answers

Simplify 6(5x-2) -4 (2x-10)

Oduvanchick [21]

30x-12-8x+40
22x-12+40
22x +28

6 0

3 years ago

Read 2 more answers

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

ANSWER:

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

SOLUTION:

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

3 years ago