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marishachu [46]

3 years ago

5

The radio station gave away a discount coupon for every twelfth and thirteenth caller. Every twentieth caller received free conc

ert tickets. Which caller was the first to get both a coupon and a concert ticket? Explain your thinking.

1 answer:

Snezhnost [94]3 years ago

7 0

Answer:

60th caller.

the 12th caller would hit a number divisible by 20 at 60.

12,24,35,48,60

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QUESTION 1 1 POINT<br> Factor: 27m3<br> 64.<br> Provide your answer below:<br> Content attribution

pickupchik [31]

Answer:

$\boxed{ \bold{ \boxed{ \sf{(3m - 4)(9 {m}^{2} + 12m + 16)}}}}$

Step-by-step explanation:

$\sf{27 {m}^{3} - 64}$

$\dashrightarrow{ \sf{( {3m)}^{3} - {(4)}^{3} }}$

Use the formula of a³ - b³ = ( a - b) ( a² + ab + b² )

$\longrightarrow{ \sf{(3m - 4)(3 {m}^{2} + 3m \times 4 + {4}^{2} }})$

$\longrightarrow{ \sf{(3m - 4)( {9m}^{2} + 12m + 16}})$

Hope I helped!

Best regards! :D

5 0

3 years ago

Solve 10e^2x - 5 =23^x for x.

yawa3891 [41]

$10e^{2x}-5=23e^x\qquad\text{subtract}\ 23e^x\ \text{from both sides}\\\\10e^{2x}-23e^x-5=0\\\\10(e^x)^2-23(e^x)-5=0\\\\\text{substitution:}\ e^x=t > 0\\\\10t^2-23t-5=0\\\\10t^2-25t+2t-5=0\\\\5t(2t-5)+1(2t-5)=0\\\\(2t-5)(5t+1)=0\iff2t-5=0\ \vee\ 5t+1=0\\\\2t=5\ \vee\ 5t=-1\\\\t=\dfrac{5}{2} > 0\ \vee\ t=-\dfrac{1}{5} < 0\\\\\text{therefore}\ e^x=\dfrac{5}{2}\to\ln e^x=\ln\left(\dfrac{5}{2}\right)\\\\\boxed{x=\ln\left(\dfrac{5}{2}\right)}$

5 0

2 years ago

Read 2 more answers

Please help me with this , it would mean alot

algol [13]

Answer:

Step-by-step explanation:

21-26. a = v - u / t

=> a = 47 - 19 / 5

=> a = 28 / 5

=> a = 5.6 m/s²

27-32. avg. speed = distance / time

=> 40 m / 10 s

=> 4 m/s

33-38. velocity = distance / time

=> v = 150 / 40

=> v = 15 / 4

=> v = 3.75 m/s

4 0

2 years ago

Find the equation of the circle whose center is at (2,3) and radius is 6

Advocard [28]

Answer:

Step-by-step explanation:

7 0

1 year ago

A person bought some cosmetics from wholesale market at the rate of Rs 360 per dozen he sells it at Rs 80 a pair find the gain p

k0ka [10]

Given,

CP of cosmetics = Rs 360 per dozen

SP of a pair of cosmetics = Rs 80

We need to find the profit percentage.

Solution,

We know that,

1 dozen = 12 items

CP of 1 cosmetic = 360/12 = Rs 30

SP of 1 cosmetic = 80/2 = Rs 40

Profit = SP-CP

= Rs 40 - Rs 30

= Rs 10

Profit percentage is given by :

$\%=\dfrac{profit}{CP}\times 100\\\\=\dfrac{10}{30}\times 100\\\\=33.34\%$

So, the profit percentage is 33.34%.

7 0

2 years ago