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Natasha_Volkova [10]
2 years ago
14

Tam sayılı kesirleri anlatır mısınız?​

Mathematics
1 answer:
Afina-wow [57]2 years ago
4 0

Bir tam sayı ve bir basit kesir ile ifade edilen kesirlere taam sayılı kesir denir.

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A regular pentagon is shown. A regular pentagon has side lengths of 9.4 centimeters and a radius of 8 centimeters. What is the l
Angelina_Jolie [31]

Answer:

6.5 cm

Step-by-step explanation:

The computation of the length of the apothem is shown below:

Given that

The side length is 9.4 centimeters

And, the radius is 8 centimeters

Now based on the above information

As per the attached figure  

AB = 8 cm

BC = 9.4 ÷ 2 = 4.7 cm

Now apply the pythagoras theorem

AB^2 = BC^2 + AC^2

8^2 = 4.7^2 + AC^2

AC^2 = 41.91

AC = 6.47 cm

= 6.5 cm

7 0
3 years ago
Create an inequality: <br><br> The sun of the numbers is not more than 12
lara31 [8.8K]

Answer:

x + y ≤ 12

Step-by-step explanation:

Inequality:

   Not more than 12 means less than or equal to 12

x + y ≤ 12

6 0
2 years ago
NEED HELP ASAP!!!
svet-max [94.6K]

Answer:

The answer is 44!

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
Write the equation of a line in slope intercept for with a slope of -6/5 and a y-intercept of (0,3)
Anettt [7]

Answer:

y=-6/5x+3.

Step-by-step explanation:

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6 0
3 years ago
Help!!!!!!!!!!!!!!!!
Andru [333]

Step-by-step explanation:

The area would be 9 times compared to the area of the original square. To test this, you can let the side of the original square be equal 1. By tripling this side, the side becomes three. Utilizing the area of a square formula, A= s^2, the area of the original square would be 1 after substituting 1 for s. Then, you do the same for the area of the tripled square. With the substitution, the area of the tripled square would be 9. This result displays the area of the tripled square being 9 times as large as the area of the original square. This pattern can be used for other measurements of the square such as:

let s = 2, Original Area= 2^2 = 4 Tripled Area= (2(3))^2 = 6^2= 36. 36/4 = 9

let s = 3, Original Area = 3^2 = 9 Tripled Area - (3(3))^2 = 9^2 =81. 81/9 = 9

let s = 4, Original Area = 4^2 = 16 Tripled Area - (4(3))^2 = 12^2 = 144. 144/16 = 9

let s = 5, Original Area = 5^2 = 25 Tripled Area - (5(3))^2 = 15^2 = 225. 225/25 = 9

let s = 6, Original Area = 6^2 = 36 Tripled Area - (6(3))^2 = 18^2 = 324. 324/36 = 9

let s = 7, Original Area = 7^2 = 49 Tripled Area - (7(3))^2 = 21^2 = 2,401. 2,401/49 = 9

You can continue to increase the length of the square and follow this pattern and it will be consistent.

7 0
3 years ago
Read 2 more answers
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