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masya89 [10]
2 years ago
13

The temperature at which the velocity of sound in air is twice its velocity at 15°C

Physics
1 answer:
Elena L [17]2 years ago
8 0

With the use of below formula, at 879 °C,  velocity will be double the velocity at 15 °C.

<h3>What is the relationship between Velocity and sound ?</h3>

The velocity of sound waves in air is proportional to the square root of Thermodynamic temperature. That is, V = K\sqrt{T}

Given that the temperature at which the velocity of sound in air is twice its velocity at 15°C, Let us make use of the formula;

(v2/v1) = √(T2 / T1)

Where

  • v2 = final velocity
  • v1 = initial velocity
  • T2 = final absolute temperature
  • T1 = initial temperature.

Recall that absolute temperature = °C + 273.

If v2 = 2 × v1 and temperature in degree Celsius = 15°C, then,

Temperature in Kelvin K = 15 + 273 = 288

Substitute all the parameters into the formula

(2 × v1)/v1 = √(T2/288)

2 = √ (T2 /288)

Square both sides

4 = (T2/288)

T2 = 4 × 288

T2 = 1152K

Temperature in degrees Celsius = 1152 - 273 = 879 °C.

Therefore, at 879 °C,  velocity will be double the velocity at 15 °C.

Learn more about sound waves here: brainly.com/question/13105733

#SPJ1

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